如何在PostScript中將字符串拆分爲數組

Question

將字符串拆分爲數組的最簡單方法是什麼？例如，通過分割空間來製作一組單詞;甚至可以創建一個字符串的所有字符的數組。

我能想到的唯一方法是在循環中使用search。因爲所有的語言都有這個功能，所以恐怕我錯過了PostScript這樣做的功能。

Answer 1

您在search運營商的正確軌道上。它的目的是執行文本字符串搜索和匹配。下面是在PostScript Language Reference Manual發現search操作總結：

search string seek search post match pre true (if found) 
     string false (if not found) 

     looks for the first occurrence of the string seek within string and 
     returns results of this search on the operand stack. The topmost 
     result is a boolean that indicates if the search succeeded. 

     If search finds a subsequence of string whose elements are equal 
     to the elements of seek, it splits string into three segments: 
     pre, the portion of string preceding the match; match, the portion 
     of string that matches seek; and post, the remainder of string. It 
     then pushes the string objects post, match, and pre on the operand 
     stack, followed by the boolean true. All three of these strings are 
     substrings sharing intervals of the value of the original string. 

     If search does not find a match, it pushes the original string 
     and the boolean false. 

     Example: 

      (abbc) (ab) search ==> (bc) (ab) () true 
      (abbc) (bb) search ==> (c) (bb) (a) true 
      (abbc) (bc) search ==>() (bc) (ab) true 
      (abbc) (B) search ==> (abbc) false 

Answer 2

%! 

%(string) (delimiter) split [(s)(t)(r)(i)(n)(g)] 
/split {    % str del 
    [ 3 1 roll  % [ str del 
    {     % [ ... str del 
     search {  % [ ... post match pre 
      3 1 roll % [ ... pre post match %ie. [ ... pre str' del 
     }{   % [ ... str 
      exit  % [ ... str %% break-from-loop 
     }ifelse 
    }loop    % [ ... 
    ]     % [ ... ] 
} def 

(string of words separated by spaces)()split == 
%-> [(string) (of) (words) (separated) (by) (spaces)] 

(string.of.words.separated.by.dots)(.)split == 
%-> [(string) (of) (words) (separated) (by) (dots)]