錯誤：「對運算符<<（std :: ostream＆，Dogs const＆）的未定義引用」

Question

在C++上，我試圖創建一個鏈接列表來追加整個類。 不過，我總是得到同樣的錯誤：

Undefined reference to operator<<std::ostream&, Dogs const&) 

我有3檔，2頭和1 CPP。

這是頭什麼樣子：

LinkedList.h：

// A class template for holding a linked list. 
#ifndef LINKEDLIST_H 
#define LINKEDLIST_H 
#include <iostream>  // For cout and NULL 
using namespace std; 

template <class T> 
class LinkedList 
{ 
private: 
    // Declare a structure for the list 
    struct ListNode 
    { 
     T value;    // The value in this node 
     struct ListNode *next; // To point to the next node 
    }; 

    ListNode *head; // List head pointer 

public: 
    // Constructor 
    LinkedList() 
     { head = NULL; } 

    // Destructor 
    ~LinkedList() {}; 

    // Linked list operations 
    void appendNode(T); 
    void displayList() const; 
}; 


//************************************************** 
// appendNode appends a node containing the value * 
// pased into newValue, to the end of the list. * 
//************************************************** 

template <class T> 
void LinkedList<T>::appendNode(T newValue) 
{ 
    ListNode *newNode; // To point to a new node 
    ListNode *nodePtr; // To move through the list 

    // Allocate a new node and store newValue there. 
    newNode = new ListNode; 
    newNode->value = newValue; 
    newNode->next = NULL; 

    // If there are no nodes in the list 
    // make newNode the first node. 
    if (!head) 
     head = newNode; 
    else // Otherwise, insert newNode at end. 
    { 
     // Initialize nodePtr to head of list. 
     nodePtr = head; 

     // Find the last node in the list. 
     while (nodePtr->next) 
     nodePtr = nodePtr->next; 

     // Insert newNode as the last node. 
     nodePtr->next = newNode; 
    } 
} 

//************************************************** 
// displayList shows the value      * 
// stored in each node of the linked list   * 
// pointed to by head.        * 
//************************************************** 

template <class T> 
void LinkedList<T>::displayList() const 
{ 
    ListNode *nodePtr; // To move through the list 

    // Position nodePtr at the head of the list. 
    nodePtr = head; 

    // While nodePtr points to a node, traverse 
    // the list. 
    while (nodePtr) 
    { 
     // Display the value in this node. 
     cout << nodePtr->value << endl; 

     // Move to the next node. 
     nodePtr = nodePtr->next; 
    } 
} 
#endif 

Dogs.h：

#ifndef Dogs_H 
#define Dogs_H 
#include <string> 
#include <iostream> 
using namespace std; 

class Dogs; 
template <class T> 

ostream& operator << (ostream&, const Dogs&); 
istream& operator >> (istream&, Dogs&); 

class Dogs 
{ 
private: 
    string dgName; 
    string dgBreed; 
    string dgColour; 
    string dgDad; 
    string dgMom; 


public: 
    Dogs(string name ="", string breed ="", string colour ="", string dad ="", string mom ="") 
    { 
     dgName = name; 
     dgBreed = breed; 
     dgColour = colour; 
     dgDad = dad; 
     dgMom = mom; 
    } 

    friend ostream& operator << (ostream&, const Dogs&); 
    friend istream& operator >> (istream&, Dogs&); 


}; 

#endif 

我真的很感激，如果你能點我出了我的問題在哪裏。 預先感謝您。

Answer 1

與模板規範

template <class T> 
^^^^^^^^^^^^^^^^^^ 
ostream& operator << (ostream&, const Dogs&); 

刪除線，不要忘記定義操作。