XSLT的屬性

Question

輸入文件格式的分組是

<Node1 Attribute11="colors" > 
    <Node2 Attribute21="Order1" Attribute22="123" Attribute23="red" /> 
    <Node2 Attribute21="Order2" Attribute22="456" Attribute23="blue" /> 
    <Node2 Attribute21="Order1" Attribute22="789" Attribute23="green" /> 
    <Node2 Attribute21="Order2" Attribute22="012" Attribute23="yellow" /> 
    <Node2 Attribute21="Order3" Attribute22="345" Attribute23="red" /> 
    <Node2 Attribute21="Order1" Attribute22="678" Attribute23="blue" /> 
</Node1> 

所需的輸出是

<Node1 Attribute11="colors" > 
    <Node3 Attribute21="Order1" > 
    <Node2 Attribute21="Order1" Attribute22="123" Attribute23="red" /> 
    <Node2 Attribute21="Order1" Attribute22="789" Attribute23="green" /> 
    <Node2 Attribute21="Order1" Attribute22="678" Attribute23="blue" /> 
    </Node3> 
    <Node3 Attribute21="Order2"> 
    <Node2 Attribute21="Order2" Attribute22="456" Attribute23="blue" /> 
    <Node2 Attribute21="Order2" Attribute22="012" Attribute23="yellow" /> 
    </Node3> 
    <Node3 Attribute21="Order3"> 
    <Node2 Attribute21="Order3" Attribute22="345" Attribute23="red" /> 
    </Node3> 
</Node1> 

隨着我沒能獲得輸出所需格式的分組。 用XSLT 1.0任何幫助非常感謝

Answer 1

XSLT 1.0解決方案測試撒克遜-HE 9.2.1.1

---

解循環：

<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> 
<xsl:output omit-xml-declaration="yes" indent="yes"/> 
<xsl:strip-space elements="*"/> 

<xsl:key name="byAttribute21" match="Node1/Node2" use="@Attribute21"/> 

<xsl:template match="node()|@*"> 
    <xsl:copy> 
    <xsl:apply-templates select="node()|@*"/> 
    </xsl:copy> 
</xsl:template> 

<xsl:template match="Node1"> 
<Node1> 
    <xsl:copy-of select="@*"/> 
    <xsl:for-each select="Node2[generate-id()=generate-id(key('byAttribute21', @Attribute21)[1])]"> 
     <Node3 Attribute21="{@Attribute21}"> 
      <xsl:apply-templates select="key('byAttribute21', @Attribute21)"/> 
     </Node3> 
    </xsl:for-each> 
</Node1> 
</xsl:template> 

</xsl:stylesheet> 

---

解無循環：

<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> 
<xsl:output omit-xml-declaration="yes" indent="yes"/> 
<xsl:strip-space elements="*"/> 

<xsl:key name="byAttribute21" match="Node1/Node2" use="@Attribute21"/> 

<xsl:template match="node()|@*"> 
    <xsl:copy> 
    <xsl:apply-templates select="node()|@*"/> 
</xsl:copy> 
</xsl:template> 

<xsl:template match="Node1"> 
    <Node1> 
     <xsl:copy-of select="@*"/> 
     <xsl:apply-templates select="*" mode="node3"/> 
    </Node1> 
</xsl:template> 

<xsl:template match="Node2[generate-id()=generate-id(key('byAttribute21', @Attribute21)[1])]" mode="node3"> 
<Node3 Attribute21="{@Attribute21}"> 
    <xsl:apply-templates select="key('byAttribute21',@Attribute21)" mode="node2"/> 
    </Node3> 
    </xsl:template> 

    <xsl:template match="Node2" mode="node2"> 
     <xsl:copy-of select="."/> 
    </xsl:template> 

</xsl:stylesheet>