無法傳遞數據庫中的值

以下是將數據發送到本地主機服務器中的MySQl數據庫的java代碼。使用的腳本語言是是php。 Php代碼工作正常，當我通過瀏覽器使用它時，值會被插入。我覺得溝通有錯誤。但我無法調試它。請幫忙。無法傳遞數據庫中的值

package com.example.databasetest1; 

    import java.io.IOException; 
    import java.util.ArrayList; 
    import java.util.List; 

    import org.apache.http.NameValuePair; 
    import org.apache.http.client.ClientProtocolException; 
    import org.apache.http.client.HttpClient; 
    import org.apache.http.client.entity.UrlEncodedFormEntity; 
    import org.apache.http.client.methods.HttpPost; 
    import org.apache.http.impl.client.DefaultHttpClient; 
    import org.apache.http.message.BasicNameValuePair; 

    import android.os.Bundle; 
    import android.app.Activity; 
    import android.view.Menu; 
    import android.view.View; 
    import android.widget.Button; 
    import android.widget.EditText; 

    public class MainActivity extends Activity { 
    Button Enter; 
    EditText tName; 
    String sName; 
     @Override 
     protected void onCreate(Bundle savedInstanceState) { 
      super.onCreate(savedInstanceState); 
      setContentView(R.layout.activity_main); 

      Enter = (Button) findViewById(R.id.bEnter); 
      tName =(EditText)findViewById(R.id.etName); 
      sName=tName.getText().toString(); 
      Enter.setOnClickListener(new View.OnClickListener() { 


       @Override 
       public void onClick(View v) { 
        // TODO Auto-generated method stub 
        try { 
         HttpClient httpClient = new   DefaultHttpClient(); 
         List<NameValuePair> nameValuePair=new ArrayList<NameValuePair>(1); 
         nameValuePair.add(new BasicNameValuePair("Name",sName)); 
         HttpPost httpPost = new HttpPost("http://192.168.173.1/try_database/name_insert.php"); 
         httpPost.setEntity(new UrlEncodedFormEntity(nameValuePair)); 
         httpClient.execute(httpPost); 
      } catch (ClientProtocolException e1) { 
         // TODO Auto-generated catch block 
         e1.printStackTrace(); 
      } catch (IOException e2) { 
       // TODO Auto-generated catch block 
       e2.printStackTrace(); 
      } 
     } 
    }); 

     } 
     /*public void insert() throws ClientProtocolException, IOException 
     { 
      HttpClient httpClient = new DefaultHttpClient(); 
      List<NameValuePair> nameValuePair=new ArrayList<NameValuePair>(1); 
      nameValuePair.add(new BasicNameValuePair("Name",sName)); 
      HttpPost httpPost = new HttpPost("http://192.168.173.1/try_database/name_insert.php"); 
      httpPost.setEntity(new UrlEncodedFormEntity(nameValuePair)); 
      httpClient.execute(httpPost); 
}*/ 

     @Override 
     public boolean onCreateOptionsMenu(Menu menu) { 
      // Inflate the menu; this adds items to the action bar if it is present. 
      getMenuInflater().inflate(R.menu.main, menu); 
      return true; 
     } 

    }

來源

2013-12-09 nik

使用的AsyncTask建立連接。 –

'我覺得在通信中有錯誤'。如果發生任何錯誤，請發佈錯誤，不要感到 –

我會將代碼移到異步並告訴ugus發生了什麼。謝謝 – nik