我有一個存儲過程(MSSQL 2K5),將採取一個變量的LIKE聖誕老人像這樣使用變量:在SQL LIKE語句
DECLARE @SearchLetter2 char(1)
SET @SearchLetter = 't'
SET @SearchLetter2 = @SearchLetter + '%'
SELECT *
FROM BrandNames
WHERE [Name] LIKE @SearchLetter2 and IsVisible = 1
--WHERE [Name] LIKE 't%' and IsVisible = 1
ORDER BY [Name]
不幸的是,目前這條線拋出一個語法錯誤,而評論where子句運行得很好。任何人都可以幫助我得到未評論的行工作?
感謝。它爲我工作 – Goldfish 2017-08-26 18:16:12