使用循環來顯示特定對象的ArrayList

Question

所以我需要有超過7.一個整數值，一個ArrayList顯示某些元素到目前爲止，我已經寫了這一點，但我掙扎，使其工作。誰能幫忙？

public Diary() 
{ 
    jobname = new ArrayList<Job>(); 
} 


public void priority() 
{ 
    int index = 0; 
    while (index < jobname.size()) { 
     Job jobName = jobname.get (index); 
     index ++; 
     //if (jobname.get (priority)) { 
     // System.out.println (jobname); 
     //} 
    } 
} 

這是由日記引用的Job類。

public Job(String job, int priorityNum, String day) 
{ 
    if (priority < 0 || priority > 10) { 
     priority = 0; 
    } 
    else { 
     priority = priorityNum; 
    } 
    jobname = job; 
    dueDay = day; 
} 

public boolean isUrgent() 
{ 
    return priority > 7; 
} 


public String toString() 
{ 
    String s = ""; 
    s += "Job = " + jobname + " \n"; 
    s += "Day Due = " + dueDay + " \n"; 
    s += "Priority = " + priority + " \n"; 

    return s; 
} 

Answer 1

在你的情況最好的選擇是「爲每個」循環。 它看起來像這樣：

for(Job job: jobname) 
{ 
    if(job.isUrgent()) System.out.println(job);  
} 

Answer 2

您需要更改您的代碼如下：其次

public void priority() 
{ 
    foreach(Job job : jobname){ 
     if (job.getPriority() > 7) { 
      System.out.println (job); 
     } 
    } 
} 

，在Job類添加getPriority()，將返回的priority值：

public String getPriority(){ 
    return this.priority; 
}