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我一直對Java項目對我來說類，而我幾乎已經完成。該程序是一個hang子手遊戲，用戶輸入一個字母，程序繼續根據字母是否在單詞中。我遇到的問題是，我無法弄清楚如何使它所以當用戶輸入一個以上的字母，數字或符號，那麼程序將打印出來，上面寫着「無效的輸入，再試一次」，並擁有了用戶的聲明再輸入一些內容，而不是將其顯示爲錯過的嘗試或不在該單詞中的「字母」。這裏是我的代碼：僅運行程序，如果輸入一個字母
import java.util.Scanner;
import java.util.Random;
import java.io.*;
public class Hangman {
private Scanner in = new Scanner(System.in);
private boardPiece[] board = {new boardPiece(0),new boardPiece(0),new boardPiece(3),
new boardPiece(1),new boardPiece(2),new boardPiece(0)};
private String puzzle;
private String puzzleWord;
private int puzzleIndex;
private Random generator = new Random(System.currentTimeMillis());
private boolean win;
private boolean over;
private String correct = "";
private char guesses[] = new char[26];
private int guessed;
private int misses;
private String puzzles[] = new String[5];
public static void main(String [] args){
String letter;
String again = "y";
Hangman game = new Hangman();
try{
BufferedReader in =
new BufferedReader(new FileReader("puzzles.txt"));
int count = 0;
while (in.ready()) { //while there is another line in the input file
game.puzzles[count] = in.readLine(); //get line of data
count++; //Increment CWID counter
}
in.close();
}
catch(IOException e){
System.out.println("Error during reading/writing");
}
System.out.println("Welcome to HangMan!");
System.out.println("To play, guess a letter to try to guess the word.");
System.out.println("Every time you choose an incorrect letter another");
System.out.println("body part appears on the gallows. If you guess the");
System.out.println("word before you're hung, you win");
System.out.println("If you get hung, you lose");
System.out.println();
System.out.println("Time to guess...");
while(again.charAt(0) == 'y'){
game.displayGallows();
while(!game.over){
game.printBoard();
game.printLettersGuessed();
System.out.println("The word so far: " + game.puzzle);
System.out.println("Choose a letter: ");
letter = game.in.next();
game.guesses[game.guessed] = letter.charAt(0);
game.guessed++;
game.sort();
if(game.puzzleWord.indexOf(letter.charAt(0)) != -1){
game.correct = game.correct + letter.charAt(0);
game.puzzle = game.puzzleWord.replaceAll("[^"+game.correct+" ]","-");
if(game.puzzleWord.replaceAll("["+game.correct+" ]","").length() == 0){
game.win = true;
game.over = true;
}
}
else
game.PrintWrongGuesses();
}
game.printBoard();
System.out.println("Solution: " + game.puzzleWord);
if(game.win)
System.out.println("Congratulations! You've solved the puzzle!");
else
System.out.println("You failed, failer!");
System.out.println();
System.out.println("Congratulations, you win!");
System.out.println("Do you want to play again? (y/n)");
again = game.in.next();
}
System.out.println("Goodbye!");
}
public void displayGallows(){
win = false;
over = false;
board[0].piece = " ______ ";
board[1].piece = " | | ";
board[2].piece = " | ";
board[3].piece = " | ";
board[4].piece = " | ";
board[5].piece = " _______| ";
puzzleIndex = generator.nextInt(puzzles.length);
puzzleWord = puzzles[puzzleIndex];
puzzle = puzzleWord.replaceAll("[A-Za-z]","-");
correct = "";
for(int x=0;x<26;x++)
guesses[x] = '~';
guessed = 0;
misses = 0;
}
public void printBoard(){
for(int x =0;x<6;x++)
System.out.println(board[x].piece);
}
public void PrintWrongGuesses(){
misses++;
System.out.println();
if(misses == 1){
board[2].piece = " 0 | ";
System.out.println("Number of misses: " + misses);
}
else if(misses == 2){
board[2].piece = " \\0 | ";
System.out.println("Number of misses: " + misses);
}
else if(misses == 3){
board[2].piece = " \\0/ | ";
System.out.println("Number of misses: " + misses);
}
else if(misses == 4){
board[3].piece = " | | ";
System.out.println("Number of misses: " + misses);
}
else if(misses == 5){
board[4].piece = " / | ";
System.out.println("Number of misses: " + misses);
}
else if(misses == 6){
board[4].piece = " /\\ | ";
System.out.println("Number of misses: " + misses);
over = true;
}
}
public void printLettersGuessed(){
System.out.print("Letters guessed already: ");
for(int x=0;x<26;x++){
if(guesses[x] != '~')
System.out.print(guesses[x] + " ");
}
System.out.println();
}
public void sort(){
boolean doMore = true;
while (doMore) {
doMore = false; // assume this is last pass over array
for (int i=0; i<guesses.length-1; i++) {
if (guesses[i] > guesses[i+1]) {
char temp = guesses[i];
guesses[i] = guesses[i+1];
guesses[i+1] = temp;
doMore = true; // after an exchange, must look again
}
}
}
}
class boardPiece{
public String piece;
public int total;
public int used;
boardPiece(int x){
used = 0;
total = x;
}
}
}
謝謝。有關如何在輸入整數時顯示相同錯誤的任何提示？ –
嗯，這不是最漂亮的解決方案，但你可以嘗試解析字符串，如果解析失敗，請繼續，即布爾confirmedNum = TRUE;嘗試{int _tmp = Integer.parseInt（letter）; } catch（Exception ex）{confirmedNum = false; } if（letter.length（）== 1 &&！confirmedNum）... – DFreeman
有人已經以一種非常簡單的方式回答了這個問題的一部分。謝謝你！ –