XML解析器 - 如何從節點獲取值

我有關於解析XML文件的問題。可以說我有XML文件：XML解析器 - 如何從節點獲取值

<line> 
    <point> 
     <X>100</X> 
     <Y>100</Y> 
    </point> 
    <point> 
     <X>200</X> 
     <Y>200</Y> 
    </point> 
</line>

，我想用DOM解析它：

DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance(); 
    DocumentBuilder dBuilder = dbFactory.newDocumentBuilder(); 
    Document doc = dBuilder.parse(f); 
    doc.getDocumentElement().normalize(); 
    NodeList nList = doc.getElementsByTagName("point"); 

    for (int temp = 0; temp < nList.getLength(); temp++) { 

     Node nNode = nList.item(temp); 

     if (nNode.getNodeType() == Node.ELEMENT_NODE) { 

      Element eElement = (Element) nNode; 

      System.out.println("x: " + eElement.getElementsByTagName("X").item(0).getTextContent());

但是 - 我怎樣才能獲得X和Y從XML文件作爲整數？ - 第一個X代表x1，第一個Y代表y1，第二個X代表x2，第二個Y代表y2？

我想：

int x1 = Integer.valueOf(eElement.getAttribute("X")); 
int y1 = Integer.valueOf(eElement.getAttribute("Y"));

但沒有成功

來源

2013-06-02 DRastislav

你的'System.out.println（）'按預期工作嗎？ – jlordo

每條線都有兩個「點」並遵循這種結構？ – acdcjunior

System.out.println的工作沒有問題 – DRastislav

// Get the <line> element 
NodeList nList = doc.getElementsByTagName("line"); 
Element line = (Element) nList.item(0); 

// Get each <point> element from the <line> 
Element point1 = (Element) line.getElementsByTagName("point").item(0); 
Element point2 = (Element) line.getElementsByTagName("point").item(1); 

// Get each <X> and <Y> from each <point> retrieved before 
Integer x1 = Integer.parseInt(point1.getElementsByTagName("X").item(0).getTextContent()); 
Integer y1 = Integer.parseInt(point1.getElementsByTagName("Y").item(0).getTextContent()); 
Integer x2 = Integer.parseInt(point2.getElementsByTagName("X").item(0).getTextContent()); 
Integer y2 = Integer.parseInt(point2.getElementsByTagName("Y").item(0).getTextContent());

整個代碼：

DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance(); 
DocumentBuilder dBuilder = dbFactory.newDocumentBuilder(); 
Document doc = dBuilder.parse(f); 
doc.getDocumentElement().normalize(); 

NodeList nList = doc.getElementsByTagName("line"); 

Element line = (Element) nList.item(0); 

Element point1 = (Element) line.getElementsByTagName("point").item(0); 
Element point2 = (Element) line.getElementsByTagName("point").item(1); 

Integer x1 = Integer.parseInt(point1.getElementsByTagName("X").item(0).getTextContent()); 
Integer y1 = Integer.parseInt(point1.getElementsByTagName("Y").item(0).getTextContent()); 
Integer x2 = Integer.parseInt(point2.getElementsByTagName("X").item(0).getTextContent()); 
Integer y2 = Integer.parseInt(point2.getElementsByTagName("Y").item(0).getTextContent()); 

System.out.println("x1: " + x1 + "\ty1: " + y1 + "\tx2: " + x2 + "\ty2: " + y2);

輸出：

x1: 100 y1: 100 x2: 200 y2: 200

來源

2013-06-02 18:35:49 acdcjunior

謝謝，它工作:) – DRastislav

XML解析器 - 如何從節點獲取值

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