如何顯示在數據庫中按名稱搜索成員

Question

PHP代碼後，共享同一個地址的所有成員迄今

<?php include 'topbit.php'; 
    if (isset($_POST['address_submitted'])) { 
    $given_name = $_POST['address']; 
    $find_address_sql = "SELECT * FROM `members` WHERE `LastName` LIKE 
    '%$given_name%' OR `FirstName` LIKE '%$given_name%' ORDER BY `LastName` 
    ASC"; 
    $find_address_query = mysqli_query($dbconnect, $find_address_sql); 
    $find_address_rs = mysqli_fetch_assoc($find_address_query); 
    $count = mysqli_num_rows($find_address_query); 
?> 

我需要的代碼以匹配該名或姓搜索數據庫搜索查詢，然後從該查詢中找到的成員的地址用於搜索數據庫中的地址與第一個查詢返回的任何成員相同的地址。我花了大約3個小時，並沒有得到任何地方，所以一些幫助將不勝感激。

Answer 1

試試這個第一個查詢結果後

foreach($find_address_rs as $key =>$value) 
    { 
     if(isset($addresses)) 
     { 
     $addresses.=','.$value['address']; 
     } 
    else 
    { 
     $addresses=$value['address']; 
    } 
     } 


    $result_members = "SELECT * FROM `members` WHERE `address` in ('".$addresses."')"; 

$members = mysqli_query($dbconnect, $result_members); 
$members_rs = mysqli_fetch_assoc($members);