我想用json創建一個登錄和註冊系統。 我想先獲取url的內容,然後解析json字符串。 Json String sample:在android中解析簡單的json字符串
{ "employee":{"mesg":"username is exsist!","id":0,"name":0,"username":0,"email":0,"status":500} }
我只需要mesg或狀態。 我無法解析它。我想解析這個字符串,每次,我的應用程序給力停止
這是我的代碼:
package com.sourcey.materiallogindemo;
import android.app.ProgressDialog;
import android.os.Bundle;
import android.support.v7.app.AppCompatActivity;
import android.util.Log;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.TextView;
import android.widget.Toast;
import butterknife.Bind;
import butterknife.ButterKnife;
public class SignupActivity extends AppCompatActivity {
//URL to get JSON Array
//JSON Node Names
public String nurl;
private static final String TAG = "SignupActivity";
@Bind(R.id.input_name) EditText _nameText;
@Bind(R.id.input_email) EditText _emailText;
@Bind(R.id.input_tell) EditText _tellText;
@Bind(R.id.input_password) EditText _passwordText;
@Bind(R.id.btn_signup) Button _signupButton;
@Bind(R.id.link_login) TextView _loginLink;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_signup);
ButterKnife.bind(this);
_signupButton.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
signup();
}
});
_loginLink.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
// Finish the registration screen and return to the Login activity
finish();
}
});
}
public void signup() {
Log.d(TAG, "Signup");
if (!validate()) {
onSignupFailed();
return;
}
_signupButton.setEnabled(false);
final ProgressDialog progressDialog = new ProgressDialog(SignupActivity.this,
R.style.AppTheme_Dark_Dialog);
progressDialog.setIndeterminate(true);
progressDialog.setMessage("در حال انجام عملیات...");
progressDialog.show();
String name = _nameText.getText().toString();
String email = _emailText.getText().toString();
String tell = _tellText.getText().toString();
String password = _passwordText.getText().toString();
// TODO: Implement your own signup logic here.
nurl = "http://someurl/json/user.php?type=register&mobile="+tell+"&p="+password+"&email="+email+"&name="+name;
//new JSONParse().execute();
new android.os.Handler().postDelayed(
new Runnable() {
public void run() {
onSignupSuccess();
progressDialog.dismiss();
}
}, 3000);
}
public void onSignupSuccess() {
_signupButton.setEnabled(true);
setResult(RESULT_OK, null);
finish();
}
public void onSignupFailed() {
Toast.makeText(getBaseContext(), "Login failed", Toast.LENGTH_LONG).show();
_signupButton.setEnabled(true);
}
public boolean validate() {
boolean valid = true;
String name = _nameText.getText().toString();
String email = _emailText.getText().toString();
String tell = _tellText.getText().toString();
String password = _passwordText.getText().toString();
if (name.isEmpty() || name.length() < 3) {
_nameText.setError("at least 3 characters");
valid = false;
} else {
_nameText.setError(null);
}
if (email.isEmpty() || !android.util.Patterns.EMAIL_ADDRESS.matcher(email).matches()) {
_emailText.setError("enter a valid email address");
valid = false;
} else {
_emailText.setError(null);
}
if (tell.isEmpty() || !android.util.Patterns.PHONE.matcher(tell).matches()) {
_tellText.setError("enter a valid phone number");
valid = false;
} else {
_tellText.setError(null);
}
if (password.isEmpty() || password.length() < 4 || password.length() > 10) {
_passwordText.setError("between 4 and 10 alphanumeric characters");
valid = false;
} else {
_passwordText.setError(null);
}
return valid;
}
}
現在我不知道我能做些什麼確切地解析字符串,得到的只是狀態或MESG,謝謝掌舵。我非常需要這個,對於一個成熟的問題感到抱歉。 關於
其中U試圖解析發佈JSON字符串 –
你有一些很好的答案顯示代碼示例代碼。我建議你使用這裏的答案之一,而不是創建一個新的問題。 – Knossos