Yii的標準問題，與外國表中選擇值

Question

嗨，我要選擇以下從table.i嘗試，但下劃線的值，它不工作....

$criteria = new CDbCriteria;  

    $criteria->select = array('description', 'id','rate','item_unit_id'); 
    $criteria->with=array("item_unit","color"); 
    $criteria->together = true; 
    $criteria->addSearchCondition("description", $_GET['query']); 

    $criteria->limit = $this->limit; 

    $items = Item::model()->findAll($criteria); 
    $suggestions = array(); 
    $x=0; 
    foreach ($items as $c) { 
     $suggestions[$x]['value'] = $c->description; 
     $suggestions[$x]['id'] = $c->id; 
     $suggestions[$x]['rate'] = $c->rate; 
     $suggestions[$x]['unit'] = $c->item_unit->name; 
     $x++; 
    } 

Answer 1

好吧，如果你將」讀過你會知道的文檔，而是因爲你沒有，你不:)

然而，這可能會幫助您：

$criteria->select = 't.id, t.description, t.rate, t.code, color.name, item_unit.name'; 
$criteria->with = array(
    "item_unit" => array(
     'together' => true, 
     'joinType' => 'INNER JOIN' 
    ), 
    "color" => array(
     'together' => true, 
     'joinType' => 'INNER JOIN', 
    ) 
); 

$criteria->addSearchCondition("t.description", $_GET['query']); 
$criteria->limit = $this->limit; 

$items = Item::model()->findAll($criteria);