以編程方式在OS X應用程序中創建和定位NSButton？

Question

我需要在Mac OS X Cocoa應用程序中以編程方式創建和定位按鈕。任何幫助，將不勝感激......

Answer 1

所有按鈕是控制和所有控件都意見，所以見，依次爲：

• 的View Programming Guide
• 的Control and Cell Programming Topics
• 的Button Programming Topics

Answer 2

正位按鈕您需要更改按鈕的原點x和y。看看我在下面寫的代碼和評論。

你可以這樣說：

-(void)awakeFromNib { 

    //Start from bottom left corner 

    int x = 100; //possition x 
    int y = 100; //possition y 

    int width = 130; 
    int height = 40; 

    NSButton *myButton = [[[NSButton alloc] initWithFrame:NSMakeRect(x, y, width, height)] autorelease]; 
    [[windowOutlet contentView] addSubview: myButton]; 
    [myButton setTitle: @"Button title!"]; 
    [myButton setButtonType:NSMomentaryLightButton]; //Set what type button You want 
    [myButton setBezelStyle:NSRoundedBezelStyle]; //Set what style You want 

    [myButton setTarget:self]; 
    [myButton setAction:@selector(buttonPressed)]; 
} 

-(void)buttonPressed { 
    NSLog(@"Button pressed!"); 

    //Do what You want here... 
} 

** WindowOutlet是窗口，所以不要忘記它IBOutlet中。