0
如何在tasm中打印負數?請任何人幫助我。 例如,如果我做減法2-7 =( - 5)。我怎樣才能打印-5?在TASM中顯示負數
如何在tasm中打印負數?請任何人幫助我。 例如,如果我做減法2-7 =( - 5)。我怎樣才能打印-5?在TASM中顯示負數
您將需要自己執行數字轉換(例如,使用您自己的功能)。我把這個兼容TASM5的Win32應用程序作爲例子,儘管我確信你可以在網上找到無數其他的數字 - >字符串轉換樣本。
對於這樣一個簡單的目標,這可能看起來很多代碼,但是如果您將「通用」功能設計爲足夠通用,以便在包含文件或庫中的任意數量的程序中使用,則真正的程序只是底部的appMain()函數,它只有大約10行代碼。爲了成爲一個完整的工作示例,我將所有內容都放在一個文件中。
您對下面顯示的numToString()函數感興趣,它將DWORD轉換爲傳遞給函數的緩衝區中的數字。其餘的代碼只是一個框架來調用函數以及一些常用的WriteConsole包裝器。 numToString()支持將數字轉換爲任何基數(例如十六進制和二進制)。在這個例子中,我傳遞參數來指定基數爲10的負標誌啓用(表示將DWORD號碼視爲已簽名)。
爲numToString()的算法如下:
-If number is to be interpreted as signed and IS negative, convert it to positive and set bHasSign flag
-Repeatedly divide positive (in loop) number by base (radix) and convert remainder to ASCII char; this gives us each digit of the resulting string starting with the least significant digit
-Append negative "-" to end based on bHasSign flag
-NULL terminate destination buffer
-Because the algorithm actually computes digits from least significant to most significant, we need to reverse the resultant string (including negative sign) before returning. In English, we read digits starting with most significant first.
The reverse algorithm swaps the outer bytes, then the next inner bytes, and so on until it reaches the middle of the string. This swapping allows us to avoid setting up a temporary buffer for the character reversal.
程序的輸出:
The number is: -352
計劃清單:
.386
.model flat
GetStdHandle PROTO STDCALL :DWORD
WriteConsoleA PROTO STDCALL :DWORD, :DWORD, :DWORD, :DWORD, :DWORD
ExitProcess PROTO STDCALL :DWORD
getStringLength PROTO STDCALL :DWORD
outputString PROTO STDCALL :DWORD, :DWORD
numToString PROTO STDCALL :DWORD, :DWORD, :DWORD, :DWORD, :DWORD
NULL equ 0
STD_OUTPUT_HANDLE equ -11
MAXLEN_BINARYNUM_BUFFER equ 33 ;max string length for number->string buffer assuming smallest base (32 bits) + NULL accounts for largest possible binary number
MAXLEN_BINARYNUM_BUFFER_AS_DWORD equ 9 ;36-byte hack for MAXLEN_BINARYNUM_BUFFER used below so TASM doesn't mess up Win32 stack alignment
CODE_ERROR_BUFLEN equ -10
.data
szMsg db 'The number is: ',0
.code
;
; getStringLength() - returns zero terminated string length in eax
;
getStringLength PROC STDCALL pszString:DWORD
;count the characters in the string and store result in ecx
lea esi,pszString ;make esi point to first character in string
mov esi,[esi]
mov edi,esi ;edi pointer to first character also
cld
@@countloop:
lodsb
cmp al,0
jne SHORT @@countloop
dec esi ;we're now pointing past NULL, so back up one
sub esi,edi ;subtract beginning pointer from pointer at NULL so that esi now contains string count
;return string length in returned in eax
mov eax,esi
ret
getStringLength ENDP
;
; outputString(pszString) - outputs a zero terminated string
; returns 0 on failure or final character count upon success (excluding NULL terminator)
;
outputString PROC STDCALL
LOCALS
ARG hConsole:DWORD
ARG pszString:DWORD
LOCAL dwCharsWrote:DWORD
;get string length (in eax)
lea esi,pszString
mov esi,[esi]
call getStringLength ,esi
;load string pointer into esi
lea esi,pszString
mov esi,[esi]
;load dwCharsWrote pointer into edx
lea edx,dwCharsWrote
;write string to console
call WriteConsoleA ,hConsole,edi,eax,edx,NULL
;if the function fails, return 0, otherwise return the characters written
cmp eax,0
jz @@funcdone
mov eax,[dwCharsWrote]
@@funcdone:
ret
outputString ENDP ;outputString()
;
; numToString() - converts unsigned DWORD to digit string
;
numToString PROC STDCALL
ARG uNum:DWORD
ARG uBase:DWORD
ARG pDest:DWORD
ARG uDestLen:DWORD
ARG bSigned:DWORD
LOCAL pEnd:DWORD
LOCAL bHasSign:DWORD
;default to number not signed
mov [bHasSign],0
;if we're interpreting number as signed, see if 32nd bit (sign flag) is set
cmp bSigned,0
jz SHORT @@setup_div_loop
test DWORD PTR [uNum],080000000h
jz SHORT @@setup_div_loop
mov [bHasSign],1 ;number is signed: set sign flag, then remove the sign
not [uNum] ; from the bits VIA: bitwise NOT, then adding 1
inc [uNum] ; this will give us an unsigned representation of the same number
; for which we will add a negative sign character at end
;setup divide/remainder loop
@@setup_div_loop:
mov edi,[pDest] ;edi points to beginning of dest buffer
mov ebx,edi ;pEnd variable will point 1 past end of buffer
add ebx,[uDestLen]
mov [pEnd],ebx
mov ebx,[uBase] ;ebx will hold the base to convert to
mov eax,uNum ;eax is our number to convert
@@divloop:
;range check buffer
cmp edi,[pEnd] ;if we are we outside of buffer?
jae SHORT @@errorbufoverflow ; we've overflowed
;setup 32-bit divide - divide eax by radix (ebx)
xor edx,edx
div ebx
;assume remainder can always fit in byte (should range check radix)
; and convert value to ASCII (values past 9 get hex digits
cmp dl,9
ja SHORT @@convletters
add dl,48 ;convert 0-9 to ASCII digits
jmp SHORT @@chardone
@@convletters:
add dl,55 ;convert A-F (letter A starts at 65, and we want to back it up by 10 to 55 such that 65 is for the value 10)
@@chardone:
mov BYTE PTR [edi],dl ;remainder goes in buffer
inc edi ;point at next character
cmp eax,0 ;if quotient nonzero, keep dividing
jnz SHORT @@divloop
;
; loop above complete
;
;do we need to add sign?
cmp [bHasSign],0
jz SHORT @@nullTerminate
; yes, range check that we have room
cmp edi,[pEnd]
jae SHORT @@errorbufoverflow
; we have room, add sign character to string
mov BYTE PTR [edi],'-'
inc edi
@@nullTerminate:
;range check buffer that we can NULL terminate the string
cmp edi,[pEnd]
jae SHORT @@errorbufoverflow
mov BYTE PTR [edi],0 ;SUCCESS - NULL terminate
;return character count in eax (not counting null)
mov eax,edi ;subtract start of buffer
sub eax,[pDest] ; from ending position of buffer to obtain count
;
; we now have correct numeric string, but with least significant digits first
; we must reverse the string to make it human-readible
;
mov esi,[pDest] ;esi is left pointer
dec edi ;edi is right pointer
@@reverseloop:
cmp esi,edi
jae SHORT @@procdone ;if esi ever meets or goes past edi, we're done!
mov dl,BYTE PTR [esi] ;swap esi and edi bytes
xchg dl,BYTE PTR [edi]
mov BYTE PTR [esi],dl
dec edi
inc esi
jmp SHORT @@reverseloop
@@errorbufoverflow:
;ERROR: buffer length too small
mov eax,CODE_ERROR_BUFLEN
@@procdone:
ret
numToString ENDP
;
; appMain()
;
appMain PROC STDCALL
LOCAL hConsole:DWORD
LOCAL szCode[MAXLEN_BINARYNUM_BUFFER_AS_DWORD]:DWORD
;get handle to console
call GetStdHandle ,STD_OUTPUT_HANDLE
mov hConsole,eax
;output message
call outputString ,hConsole,OFFSET szMsg
;this is your negative value
mov eax,-352
;convert value to string
lea esi,[szCode]
call numToString ,eax,10,esi,MAXLEN_BINARYNUM_BUFFER,1
;output number buffer
lea esi,[szCode]
call outputString ,hConsole,esi
ret
appMain ENDP
;
; Program Entry Point
;
_start:
call appMain
call ExitProcess ,eax
end _start
的可能的複製[如何使用負數作爲一個在組裝?](http://stackoverflow.com/questions/14817184/how-to-use-negative-numbers-as-one-in-assembly) – JJJ