-1
我已經在下面寫了這個循環。它在第一次迭代中執行得非常好;然而，在第二次迭代時，它返回下列錯誤：循環無法正常工作
Unable to locate element:
{"method":"xpath","selector":"html/body/header[2]/div[2]/nav/ul/li[2]/a"}`
Command duration or timeout: `120.06` seconds
環路代碼提到如下：
Workbook w2;
w2 = Workbook.getWorkbook(new File("C:\\Users\\pcs\\Desktop\\flightdata.xls")); //flight data destintion location will be same as source from flight data.
Sheet s2 = w2.getSheet(0);
for (k = 1; k < s2.getRows(); k++)
{
//redeem flow
d1.findElementByXPath("html/body/header[2]/div[2]/nav/ul/li[2]/a").click();
d1.findElementByXPath("html/body/header[2]/div[2]/nav/ul/li[2]/ul/li[3]/a").click();
d1.findElement(By.xpath("html/body/section/div[1]/form/div/div[2]/div[1]/div/div[1]/input")).sendKeys(s2.getCell(0, k).getContents());
//pause for list to be populated
try
{
Thread.sleep(1000L);
}
catch (Exception e)
{
}
//Get all items in autocomplete list
List<WebElement> items1 = d1.findElements(By.xpath("html/body/ul/li[3]/a"));
//Look for item
for(i= 0; i <items1.size();i++)
{
if(items1.get(i).getText().contains(s2.getCell(0, k).getContents()))
{
items1.get(i).click();
break;
}
}
//calendar handling
d1.findElementById("checkin").click();
d1.findElementByXPath("html/body/div[2]/div[2]/div/a/span").click();
d1.findElementByXPath("html/body/div[2]/div[2]/table/tbody/tr[3]/td[3]/a").click();
//Select Number of Rooms
d1.findElementById("roomscount").sendKeys("1");
//Select Room type
d1.findElementById("roomtype").sendKeys("Single");
//Occupant's Nationality
d1.findElementById("nationality").sendKeys("India");
//Click search button
d1.findElementByXPath("html/body/section/div[1]/form/div/div[2]/div[4]/input").click();
//after 2 min wait
d1.manage().timeouts().implicitlyWait(120, TimeUnit.SECONDS);
}
POST SEARCH HTML PAGE
<!DOCTYPE html>
<html>
<head>
<body class="" ondrop="return false;" ondragstart="return false;" onunload="" onpageshow="if (event.persisted) noBack();" onload="noBack();">
<header>
<div class="logo">
<div class="right">
<ul class="login">
<nav class="links">
<ul>
<li>
<li>
<a href="#">Redeem sMiles</a>
<ul>
<li class="pointer sprite"> </li>
<li class="flight">
<li class="hotel">
<a href="hotel.html?action=hotels">
<span class="sprite"> </span>
Hotels
</a>
</li>
<li class="smiles">
</ul>
</li>
</ul>
</nav>
<div class="clear"></div>
</div>
<div class="clear"></div>
</header>
<div class="clear"></div>
<script src="/fm/travel/js/hotel.js" type="text/javascript">
<meta content="text/html; charset=utf-8" http-equiv="Content-Type">
<link type="text/css" rel="stylesheet" href="/fm/styles/demo_table_jui.css">
<link rel="stylesheet" href="/fm/travel/styles/ui-lightness/jquery-ui-1.10.4.css">
<link rel="stylesheet" href="/fm/travel/styles/ui-lightness/autocomplete.css">
<script src="/fm/travel/js/jquery-1.10.2.js" type="text/javascript">
<script src="/fm/travel/js/jquery-ui-1.10.4.js" type="text/javascript">
<script src="http://maps.googleapis.com/maps/api/js?key=AIzaSyDY0kkJiTPVd2U7aTOAwhc9ySH6oHxOIYM&sensor=false">
<script type="text/javascript">
<script type="text/javascript">
<script type="text/javascript">
<div id="loader" style="display: none;">
<div id="modifySearchBlock" style="display: block;">
<div class="clear"></div>
<footer>
<script src="/fm/travel/js/jquery.js">
<script src="/fm/js/bootstrap.min.js">
<script src="/fm/js/jquery.meanmenu.js">
<script>
<script src="/fm/js/jquery.simpleGal.js">
<script>
<script src="/fm/js/owl.carousel.js">
<script>
<div id="ui-datepicker-div" class="ui-datepicker ui-widget ui-widget-content ui-helper-clearfix ui-corner-all"></div>
<ul id="ui-id-1" class="ui-autocomplete ui-front ui-menu ui-widget ui-widget-content ui-corner-all " tabindex="0" style="display: none;"></ul>
</body>
</html>
上面代碼屬於我搜索完成後返回的頁面。
我又需要去下面的鏈接進行搜索：
<li class="flight">
<li class="hotel">
<a href="hotel.html?action=hotels">
<span class="sprite"> </span>
Hotels
</a>
</li>
<li class="smiles">
</ul>
</li>
上面的代碼屬於我需要點擊該鏈接。請提供相同的建議。
你的選擇器是**非常脆** ..你能分享一些HTML，所以我們可以給一些建議嗎？ – sircapsalot
sure ..你需要後搜索頁面的HTML或預搜索頁面的HTML嗎？ –
兩者，只是將它包含在你的答案中。最重要的是，分享你的xpath選擇的html元素。 – sircapsalot