0
我正在製作一個內容管理系統。我允許用戶通過一個可以在新頁面上使用的表單發佈一些信息（比如「頁面標題」和「輪播速度」），但我很努力地將這些信息輸入到生成的頁面。將POST數據輸出到<<<'EOT'
要添加我正在使用的網站的內容$page .= <<<'EOT'並將html放置在那裏，但試圖在此範圍內回顯$_POST變量意味着PHP代碼將在字面上出現，因爲我將它寫入EOT而不是作爲結果。
有沒有辦法告訴EOT將<?php echo $_POST['speed'] ?>視爲異常？
<?php
$addTo = $_POST['addTo'];
//$visit = $_POST['visit'];
$dir = $_POST['name'];
$desc = $_POST['desc'];
$dir = preg_replace('/\s+/', '_', $dir);
mkdir($addTo.'/'.$dir, 0777);
mkdir($addTo.'/'.$dir.'/photos', 0777);
//Make page
$content = "he";
$myfile = fopen ($addTo.'/'.$dir.'/index.php', "w") or die ("Unable to open file!");
$page = "";
$speed = $_POST['speed'];
$page .= <<<'EOT'
<head>
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css" integrity="sha384-BVYiiSIFeK1dGmJRAkycuHAHRg32OmUcww7on3RYdg4Va+PmSTsz/K68vbdEjh4u" crossorigin="anonymous">
<script src="https://code.jquery.com/jquery-3.1.0.min.js" integrity="sha256-cCueBR6CsyA4/9szpPfrX3s49M9vUU5BgtiJj06wt/s=" crossorigin="anonymous"></script>
<script src="https://use.fontawesome.com/2c6a42bed3.js"></script>
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/js/bootstrap.min.js"></script>
</head>
<body>
<div id="myCarousel" class="carousel slide" data-ride="carousel">
<!-- Indicators -->
<ol class="carousel-indicators" style="display:none">
<li data-target="#myCarousel" data-slide-to="0" class="active"></li>
<li data-target="#myCarousel" data-slide-to="1"></li>
<li data-target="#myCarousel" data-slide-to="2"></li>
<li data-target="#myCarousel" data-slide-to="3"></li>
</ol>
<!-- Wrapper for slides -->
<div class="carousel-inner" role="listbox">
<?php
$active = "active";
$url = $_SERVER['REQUEST_URI'].'photos/';
//echo $url." - url<br/>";
$conn = mysqli_connect("localhost","root","","test");
$sql = "SELECT speed FROM pages WHERE title = ''";
if (mysqli_connect_errno()) {echo "Failed to connect to MySQL: " . mysqli_connect_error();}
$sql = "SELECT * FROM photos WHERE url = '$url'";
$result = mysqli_query($conn, $sql);
while($row = mysqli_fetch_array($result)) {
?>
<div class="item <?=$active?>">
<img src="<?php echo $row['url'].$row['caption']; ?>">
</div>
<?php
$active="";
}
$conn->close();
?>
</div>
<!-- Left and right controls -->
<a class="left carousel-control" href="#myCarousel" role="button" data-slide="prev">
<span class="glyphicon glyphicon-chevron-left" aria-hidden="true"></span>
<span class="sr-only">Previous</span>
</a>
<a class="right carousel-control" href="#myCarousel" role="button" data-slide="next">
<span class="glyphicon glyphicon-chevron-right" aria-hidden="true"></span>
<span class="sr-only">Next</span>
</a>
</div>
</body>
<script type="text/javascript">
$(document).ready(function(){
$("#myCarousel").carousel({
interval : 420,
pause: false
});
});
</script>
%s
EOT;
?>
<?php
$output = sprintf($page, $speed);
echo $output;
fwrite($myfile, $page);
fclose($myfile);
$conn = mysqli_connect("localhost","root","","test");
if (mysqli_connect_errno()) {echo "Failed to connect to MySQL: " . mysqli_connect_error();}
$sql = "INSERT INTO pages (title, type, description, active, speed) VALUES ('$dir', '$addTo','$desc' , '1', '$speed')";
if ($conn->query($sql) === TRUE) {
echo "New record created successfully";
} else {
echo "Error: " . $sql . "<br>" . $conn->error;
}
$conn->close();
//Redirect
if (isset($visit)){
//header('Location:index.php?newPage='.$addTo.'/'.$dir.'/'.$filename);
}
else {
//header('Location:index.php?newPage='.$addTo.'/'.$dir.'/'.$filename);
}
?>
你如何在你的php echo聲明中連接。這很容易。 <？php echo'............................................. ........'。 $ _ POST [「速度」。 ....';你可以寫許多行php –