ui-grid從自定義排序算法中獲取當前列（字段）名稱？

Question

一旦定義自定義排序爲列像Github和UI-Grid

你怎麼會從內部的算法訪問列？

var myAwesomeSortFn = function(a,b, rowA, rowB, direction){ 

     // "Need to access the name (field) of column being sorted here"; 
     var column = "No Idea" 

     console.log("sorting by column " + column); 

     if (a == b) return 0; 
     if (a < b) return -1; 
     if (a > b) return 1; 


    }; 

Answer 1

你可以嘗試以下...

{ field: 'lastName', displayName: 'Last Name', sortingAlgorithm: MyService.getSortingAlgorithm('lastName') }, 

然後在服務定義（或者在你的範圍，如果你喜歡）

getSortingAlgorithm: function (columnName) { 
    return function(a, b, rowA, rowB, direction) { 
     console.log("sorting by column " + columnName); 

     if (a == b) return 0; 
     if (a < b) return -1; 
     if (a > b) return 1; 
    }; 
}