谷歌的網頁排名的Java api

Question

我想獲得給定域的谷歌網頁排名。

我用下面的代碼google api代碼來得到pagerank.I得到了頁面排名到了今天，當我試圖運行相同的文件時，我得到了一些問題，並得到正確的頁面排名。

import java.net.URLConnection; 
import java.net.URL; 
import java.io.InputStream; 

/** 
* <b>PageRankService provides simple API to Google PageRank Technology</b> 
* <br> 
* PageRankService queries google toolbar webservice and returns a 
* google page rank retrieved from one of the next datacenters on the list. 
* <br>toolbarqueries.google.com 
* <br>64.233.161.100 
* <br>64.233.161.101 
* <br>64.233.177.17 
* <br>64.233.183.91 
* <br>64.233.185.19 
* <br>64.233.189.44 
* <br>66.102.1.103 
* <br>66.102.9.115 
* <br>66.249.81.101 
* <br>66.249.89.83 
* <br>66.249.91.99 
* <br>66.249.93.190 
* <br>72.14.203.107 
* <br>72.14.205.113 
* <br>72.14.255.107 
*/ 
public class PageRankService { 

    static private int dataCenterIdx = 0; 

    /** 
    * List of available google datacenter IPs and addresses 
    */ 
    static final public String [] GOOGLE_PR_DATACENTER_IPS = new String[]{ 
       "64.233.161.100", 
       "64.233.161.101", 
       "64.233.177.17", 
       "64.233.183.91", 
       "64.233.185.19", 
       "64.233.189.44", 
       "66.102.1.103", 
       "66.102.9.115", 
       "66.249.81.101", 
       "66.249.89.83", 
       "66.249.91.99", 
       "66.249.93.190", 
       "72.14.203.107", 
       "72.14.205.113", 
       "72.14.255.107", 
       "toolbarqueries.google.com", 
       }; 

    /** 
    * Default constructor 
    */ 
    public PageRankService() { 

    } 

    /** 
    * Must receive a domain in form of: "http://www.domain.com" 
    * @param domain - (String) 
    * @return PR rating (int) or -1 if unavailable or internal error happened. 
    */ 
    public int getPR(String domain) { 

     int result = -1; 
     JenkinsHash jHash = new JenkinsHash(); 

     String googlePrResult = ""; 

     long hash = jHash.hash(("info:" + domain).getBytes()); 

     String url = "http://"+GOOGLE_PR_DATACENTER_IPS[dataCenterIdx]+"/search?client=navclient-auto&hl=en&"+ 
       "ch=6"+hash+"&ie=UTF-8&oe=UTF-8&features=Rank&q=info:" + domain; 

     try { 
      URLConnection con = new URL(url).openConnection(); 
      InputStream is = con.getInputStream(); 
      byte [] buff = new byte[1024]; 
      int read = is.read(buff); 
      while (read > 0) { 
       googlePrResult = new String(buff, 0, read); 
       read = is.read(buff); 
      } 
      googlePrResult = googlePrResult.split(":")[2].trim(); 
      result = new Long(googlePrResult).intValue(); 
     } catch (Exception e) { 
      e.printStackTrace(); 
     } 

     dataCenterIdx++; 
     if (dataCenterIdx == GOOGLE_PR_DATACENTER_IPS.length) { 
      dataCenterIdx = 0; 
     } 

     return result; 

    } 

    public static void main(String [] args) { 
     long start = System.currentTimeMillis(); 
     PageRankService prService = new PageRankService(); 
     String domain = "http://www.gmail.com"; 
     if (args.length > 0) { 
      domain = args[0]; 
     } 
     System.out.println("Checking " + domain); 
     System.out.println("Google PageRank: " + prService.getPR(domain)); 
     System.out.println("Took: " + (System.currentTimeMillis() - start) + "ms"); 
    } 
} 

但今天，我不能讓網頁排名。我正在以下錯誤：

Checking http://www.google.com 
Google PageRank: -1 
java.io.IOException: Server returned HTTP response code: 504 for URL: http://64.233.161.100/search?client=navclient-auto&hl=en&ch=63513778613&ie=UTF-8&oe=UTF-8&features=Rank&q=info:http://www.google.com 
Took: 179711ms 
    at sun.net.www.protocol.http.HttpURLConnection.getInputStream(HttpURLConnection.java:1625) 
    at PageRankService.getPR(PageRankService.java:82) 
    at PageRankService.main(PageRankService.java:112) 
BUILD SUCCESSFUL (total time: 3 minutes 0 seconds) 

我要去的地方錯了嗎？

Answer 1

我不是專家，但嘗試使用http://toolbarqueries.google.com/tbr？代替/搜索