Android的HTTPS登錄

Question

我試圖寫一個Android應用程序，這將讓我從一個網站，對我的工作名冊https://www.blahblahblahcompany.com/Rostering/exportRoster.aspx

這是可能閱讀的文本？我能否通過網站驗證自己，然後下載源代碼？

有問題的網站上也有名冊問題 http://img528.imageshack.us/img528/9954/rosterf.png

Answer 1

我不知道如果我得到你真正想做的事，但我敢肯定，至少，你會需要一些GET/POST操作來執行認證proccess和檢索數據/信息。請檢查下面的方法：

public StringBuilder post(String url, List<NameValuePair> nvps) { 
    try { 
     HttpPost httppost = new HttpPost(url); 
     // if there is cookies, set then 
     if (cookies != null && cookies.size() > 0) { 
      String cookieString = ""; 
      for (int i = 0; i < cookies.size(); ++i) { 
       cookieString += cookies.get(i).getName() + "=" + cookies.get(i).getValue() + "; "; 
      } 
      cookieString += "domain=" + Constants.BaseUrl + "; " + "path=/"; 
      httppost.addHeader("Cookie", cookieString); 
     } 
     // connection timeout options 
     HttpParams httpParameters = new BasicHttpParams(); 
     HttpConnectionParams.setConnectionTimeout(httpParameters, Constants.timeoutConnection); 
     HttpConnectionParams.setSoTimeout(httpParameters, Constants.timeoutSocket); 
     // setup the post method 
     DefaultHttpClient httpClient = new DefaultHttpClient(httpParameters); 
     httppost.setEntity(new UrlEncodedFormEntity(nvps, HTTP.UTF_8)); 
     HttpResponse response = httpClient.execute(httppost); 
     BufferedReader reader = new BufferedReader(new InputStreamReader(response.getEntity().getContent(), "UTF-8")); 
     StringBuilder builder = new StringBuilder(); 
     for (String line = null; (line = reader.readLine()) != null;) 
      builder.append(line).append("\n"); 
     // set cookies 
     List<Cookie> incomingCookies = httpClient.getCookieStore().getCookies(); 
     for (int i = 0; incomingCookies != null && i < incomingCookies.size(); i++) { 
      cookies.add(incomingCookies.get(i)); 
     } 
     return builder; 
    } catch (UnsupportedEncodingException e) { 
    } catch (ClientProtocolException e) { 
    } catch (IOException e) { 
    } catch (Exception e) { 
    } 
    return null; 
} 

上面mehod執行在URL字符串參數後，使用所述一對值nvps作爲用於報頭參數。需要注意的是常量類是正在爲您的WebService聲明靜態字符串（如API條目）類，和現場餅乾的是，該怎麼保持你的會話問題餅乾的列表。此方法將以字符串構建器對象的形式返回POST請求的結果。基本上，這是一種通用的方法，可以在多種情況下使用，而且您應該做適應性調整以適應任務。這是你可以用來認證。

還有另外一個重要的方法，在HTTP GET：

public StringBuilder get(String url) { 
    try { 
     HttpGet httpget = new HttpGet(url); 
     // if there is cookies, set then 
     if (cookies != null && cookies.size() > 0) { 
      String cookieString = ""; 
      for (int i = 0; i < cookies.size(); ++i) { 
       cookieString += cookies.get(i).getName() + "=" + cookies.get(i).getValue() + "; "; 
      } 
      cookieString += "domain=" + Constants.BaseUrl + "; " + "path=/"; 
      httpget.addHeader("Cookie", cookieString); 
     } 
     HttpParams httpParameters = new BasicHttpParams(); 
     HttpConnectionParams.setConnectionTimeout(httpParameters, Constants.timeoutConnection); 
     HttpConnectionParams.setSoTimeout(httpParameters, Constants.timeoutSocket); 
     DefaultHttpClient httpClient = new DefaultHttpClient(httpParameters); 
     HttpResponse response = httpClient.execute(httpget); 
     BufferedReader reader = new BufferedReader(new InputStreamReader(response.getEntity().getContent(), "UTF-8")); 
     StringBuilder builder = new StringBuilder(); 
     for (String line = null; (line = reader.readLine()) != null;) 
      builder.append(line).append("\n"); 
     // set cookies 
     List<Cookie> incomingCookies = httpClient.getCookieStore().getCookies(); 
     for (int i = 0; incomingCookies != null && i < incomingCookies.size(); i++) { 
      cookies.add(incomingCookies.get(i)); 
     } 
     return builder; 
    } catch (UnsupportedEncodingException e) { 
    } catch (ClientProtocolException e) { 
    } catch (IOException e) { 
    } catch (Exception e) { 
    } 
    return null; 
} 

這一次做的步驟相似的序列，但有不同的用途。考慮到您已經通過身份驗證或者不需要身份驗證過程，這個目標的目標是檢索信息。它以字符串生成器的形式返回請求的數據。

請注意，除了這些方法都很一般，必須仔細檢查什麼是你所請求的網頁中使用的proccess。希望它能以某種方式幫助你！ ;-)

Answer 2

導出爲.xls文件

截圖頁面在Android網頁瀏覽器，進入工具>選項>加密的能力>查看證書以查看支持的證書提供者列表。只要您從支持的供應商購買證書，您就可以做到這一點。 Here is a stack answer可能有一些線索。