將字符串替換爲Int

Question

#! /usr/bin/env ruby 

filepath = "chapter1.xhtml" 
text = File.read(filepath) 


i=1 

text = File.read(filepath) 

while i!=91 


replace = text.gsub(/123123/) do |match| 
    match=i.to_s() 
end 
File.open(filepath, "w") {|file| file.puts replace} 
    i=i+1 
end 

我想將Ruby1，Ruby1，Ruby1替換爲Ruby1，Ruby2，Ruby3 但我的代碼不起作用。哪裏是我的錯，我該如何解決？

對於實例

Ruby1 Ruby1 Ruby1

更換到

Ruby1 Ruby2 Ruby3

Answer 1

text = File.read(filepath)讀取整個文件，讓您在循環反覆地讀它。

同上爲File.open，你刪除文件的90倍。

My code doesn't work. 

你還是解釋發生了什麼，錯誤信息等

Answer 2

input_path = "chapter1.xhtml" 
output_path = "new.txt" 
#input = 'input file <section id="bolum1"> <section id="bolum1"> <section id="bolum1">' 
string_to_replace = 'bolum1' 
File.open(output_path, "w") do |output| 
    File.open(input_path, 'r') do |f| 
     f.readlines.each do |line| 
      counter = 0 
#   result = input.gsub(string_to_replace) do |match| 
      result = line.gsub(string_to_replace) do |match| 
#    puts "found=#{match}" 
       counter += 1 
       match[-1, 1] = counter.to_s # replace last char by counter 
#    puts "replace=#{match}" 
       match # the result of the block replaces the matched string 
      end 
      p result 
      output.write(result) 
     end 
    end # input file will automatically be closed at the end of the block 
end # output file will automatically be closed at the end of the block 

文件chapter1.xhtml：

input file <section id="bolum1"> <section id="bolum1"> <section id="bolum1"> 
input file <section id="bolum1"> <section id="bolum1"> <section id="bolum1"> 

執行：

$ ruby -w t.rb 
"input file <section id=\"bolum1\"> <section id=\"bolum2\"> <section id=\"bolum3\">\n" 
"input file <section id=\"bolum1\"> <section id=\"bolum2\"> <section id=\"bolum3\">" 

我不確定這是否是正確的解決方案b因爲我不知道你的意見。它是XML嗎？使用適當的XML庫可能會更好。它更復雜嗎？也許輸入必須用的語法進行解析。請參閱www.antlr4.org和http://pragprog.com/book/tpantlr2/the-definitive-antlr-4-reference。這本書的源代碼是免費的，包含語法解析XML。

希望有所幫助。 B