我在這裏是全新的,所以我對這裏的寫作風格不是很熟悉,所以如果問題看起來不像應該那麼抱歉。 我的問題是,我如何創建一個對象數組,但不是默認的構造函數? 如果我有這樣的事情:如何在創建對象數組時避免默認的構造函數?
set<movie> a(3);
set<movie> b(2);
和構造: 對於電影
movie::movie()
{
this->naziv=0;
this->reditelj=0;
this->trajanje=0;
}
movie::movie(char *name, char *red, int len)
{
this->naziv=new char[strlen(name)+1];
strcpy(naziv,name);
this->reditelj=new char[strlen(red)+1];
strcpy(reditelj,red);
this->trajanje=len;
}
而對於集:
template<class t>
set<t>::set()
{
this->br=0;
this->niz=0;
}
set<t>::set(int b)
{
this->br=b;
this->niz=new t[br];
}
答案是偉大的,但當然,他們教給我們一些關於C++的基本知識,如何創建類,模板類,我的意思是,從一開始就編寫程序,所以現在我們不使用那些大多數喲你提到。這個任務就是用這種方式編寫代碼,那我該怎麼做呢? 這個任務是做一個類和一個模板類,模板類實際上是一個對象數組,所以我應該創建一個對象,這是一個對象數組和其他一些函數。
這裏是我的全部代碼:
Set.h
#pragma once
#include<iostream>
using namespace std;
template<class t>
class set
{
int br;
t* niz;
public:
set();
set(int b);
~set();
set(set& copy);
int vrati_br_elem()
{
return br;
}
bool pripada(t elem);
set operator*(set& drugi);
friend istream& operator>> <>(istream& ulaz,set<t> &s);
friend ostream& operator<< <>(ostream& izlaz,set<t> &s);
};
template<class t>
set<t>::set()
{
this->br=0;
this->niz=0;
}
template<class t>
set<t>::set(int b)
{
this->br=b;
this->niz=new t[br];
}
template<class t>
set<t>::~set()
{
if(this->niz!=0)
delete [] niz;
}
template<class t>
bool set<t>::pripada(t elem)
{
for(int i=0;i<this->br;i++)
if(this->niz[i]=elem)
return true;
return false;
}
template<class t>
set<t> set<t>::operator *(set<t> &drugi)
{
int broj=0;
set<t> pom((this->br>drugi.br)?this->br:drugi.br);
for(int i=0;i<this->br;i++)
for(int j=0;j<drugi.br;j++)
if(this->niz[i]==drugi.niz[j])
pom.niz[broj++]=this->niz[i];
pom.br=broj;
return pom;
}
template<class t>
istream& operator>>(istream& ulaz,set<t> &s)
{
for(int i=0;i<s.br;i++)
cin>>s.niz[i];
return ulaz;
}
template<class t>
ostream& operator<<(ostream& izlaz,set<t> &s)
{
for(int i=0;i<s.br;i++)
cout<<endl<<s.niz[i]<<endl;
return izlaz;
}
template<class t>
set<t>::set(set<t> ©)
{
this->br=copy.br;
this->niz=new t[br];
for(int i=0;i<this->br;i++)
this->niz[i]=copy.niz[i];
}
movie.h
#include<iostream>
using namespace std;
class movie
{
char* naziv;
char* reditelj;
int trajanje;
public:
movie();
~movie();
movie(movie& copy);
movie(char* name,char* red,int len);
movie& operator=(movie& film);
bool operator==(movie& film);
friend istream& operator>>(istream& ulaz,movie& film);
friend ostream& operator<<(ostream& izlaz,movie& film);
};
movie.cpp
#include"movie.h"
using namespace std;
movie::movie()
{
this->naziv=0;
this->reditelj=0;
this->trajanje=0;
}
movie::~movie()
{
if(naziv!=0&&reditelj!=0)
{
delete [] naziv;
delete [] reditelj;
}
}
movie::movie(movie ©)
{
this->naziv=new char[strlen(copy.naziv)+1];
strcpy(this->naziv,copy.naziv);
this->reditelj=new char[strlen(copy.reditelj)+1];
strcpy(this->reditelj,copy.reditelj);
this->trajanje=copy.trajanje;
}
movie& movie::operator =(movie &film)
{
if(this!=&film)
{
delete [] naziv;
delete [] reditelj;
this->naziv=new char[strlen(film.naziv)+1];
strcpy(this->naziv,film.naziv);
this->reditelj=new char[strlen(film.reditelj)+1];
strcpy(this->reditelj,film.reditelj);
this->trajanje=film.trajanje;
}
return *this;
}
bool movie::operator ==(movie &film)
{
if(!strcmp(this->naziv,film.naziv)&&!strcmp(this->reditelj,film.reditelj)&&this->trajanje==film.trajanje)
return true;
return false;
}
istream& operator>>(istream& ulaz,movie& film)
{
ulaz>>film.naziv>>film.reditelj>>film.trajanje;
return ulaz;
}
ostream& operator<<(ostream& izlaz,movie& film)
{
izlaz<<endl<<film.naziv<<endl<<film.reditelj<<endl<<film.trajanje<<endl;
return izlaz;
}
movie::movie(char *name, char *red, int len)
{
this->naziv=new char[strlen(name)+1];
strcpy(naziv,name);
this->reditelj=new char[strlen(red)+1];
strcpy(reditelj,red);
this->trajanje=len;
}
'std :: allocator',可能用'std :: uninitialized_copy'或'std :: uninitialized_fill'。 – 2012-01-04 22:43:03
另外,不要將你的班級命名爲'set',否則你會迷惑每個人。 'std :: set'比你所做的更爲人所知。另外,歡迎來到堆棧溢出。 – 2012-01-04 22:43:55
您是否嘗試使構造函數爲私有?順便說一句。你的問題格式很好:-) – rekire 2012-01-04 22:44:26