使用下面的擴展類(需要Newtonsoft JSON庫),您可以得到任何對象的JSON字符串有或沒有可讀的格式。
使用該類獲取可讀的JSON字符串;
var p = await wc.GetProducts(new Dictionary<string, string>() {
{ "orderby", "id" }, { "filter[search]", "1884" }
});
var jsonString = p.ToFormattedJsonString();
Debug.WriteLine(jsonString);
使用該類獲取一個沒有格式的普通JSON字符串;
var p = await wc.GetProducts(new Dictionary<string, string>() {
{ "orderby", "id" }, { "filter[search]", "1884" }
});
var jsonString = p.ToJsonString();
Debug.WriteLine(jsonString);
您還可以通過添加您自己的擴展方法(如下面)來簡化上述操作;
public static void ToDebug(this object data)
{
Debug.WriteLine(data.ToFormattedJsonString());
}
擴展類;
using System.Text;
using Newtonsoft.Json;
namespace System
{
public static class JsonExtensions
{
public static string ToFormattedJsonString(this object obj, bool indentWithTab)
{
return indentWithTab
? ToFormattedJsonString(obj, "\t")
: ToFormattedJsonString(obj);
}
public static string ToFormattedJsonString(this object obj, string indentString = " ")
{
return FormatJson(obj.ToJsonString(), indentString);
}
public static string ToJsonString(this object obj)
{
return JsonConvert.SerializeObject(obj);
}
public static T DeserializeJsonString<T>(this string jsonString)
{
return JsonConvert.DeserializeObject<T>(jsonString);
}
private static string FormatJson(string jsonString, string indentString)
{
var indent = 0;
var quoted = false;
var builder = new StringBuilder();
for (var i = 0; i < jsonString.Length; i++)
{
var character = jsonString[i];
switch (character)
{
case '{':
case '[':
builder.Append(character);
if (!quoted)
{
builder.AppendLine();
builder.RepeatAppend(++indent, indentString);
}
break;
case '}':
case ']':
if (!quoted)
{
builder.AppendLine();
builder.RepeatAppend(--indent, indentString);
}
builder.Append(character);
break;
case '"':
builder.Append(character);
bool escaped = false;
var index = i;
while (index > 0 && jsonString[--index] == '\\')
escaped = !escaped;
if (!escaped)
quoted = !quoted;
break;
case ',':
builder.Append(character);
if (!quoted)
{
builder.AppendLine();
builder.RepeatAppend(indent, indentString);
}
break;
case ':':
builder.Append(character);
if (!quoted)
builder.Append(" ");
break;
default:
builder.Append(character);
break;
}
}
return builder.ToString();
}
public static StringBuilder RepeatAppend(this StringBuilder builder, int count, string format,
params object[] parameters)
{
if (count <= 0 || string.IsNullOrEmpty(format))
return builder;
for (int i = 0; i < count; i++)
{
builder.AppendFormat(format, parameters);
}
return builder;
}
}
}
使用老式的foreach循環不會做你嗎? – apomene
我發現將複雜數據記錄到調試的最簡單方法是將對象簡單地序列化爲JSON字符串,因爲它僅用於調試目的,性能不應該成爲實際應用程序中的問題。我會發佈一個經常用於此目的的類和示例用法。 – mbrdev
非常感謝@mbrdev – Eugene