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我正在創建一個「回顯」服務器,它在收到消息後將其簡單地發送回去。我設法讓多客戶端工作,但我想做出某種斷開連接檢測。我嘗試通過從服務器發送單個字符,然後用客戶端中的另一個字符來回復它。不過,我無法得到這個工作。檢測插座中的斷開連接
你會如何建議我去斷開連接檢測?
MessageServer.java
import java.net.*;
import java.io.*;
public class MessageServer {
static int clientCount = 0;
public static void main(String[] args) throws IOException {
try(ServerSocket servSocket = new ServerSocket(16384)){
while(true){
Socket socket = servSocket.accept();
addClient();
new ServerThread(socket, clientCount).start();
}
} catch(IOException e) {
System.out.println("Exception caught when trying to listen on port 16384 or listening for a connection");
System.out.println(e.getMessage());
}
}
public static void addClient(){
clientCount++;
}
}
ServerThread.java
import java.net.*;
import java.io.*;
public class ServerThread extends Thread {
private Socket cltSocket;
private BufferedReader in;
private PrintWriter out;
private int num;
public ServerThread(Socket clientSocket, int count) {
cltSocket = clientSocket;
num = count;
}
public void run() {
String input;
try {
out = new PrintWriter(cltSocket.getOutputStream(), true);
in = new BufferedReader(new InputStreamReader(cltSocket.getInputStream()));
System.out.println("Client " + num + " connected!");
while(cltSocket.isConnected() && !cltSocket.isClosed()){
if(in.ready()){
input = in.readLine();
if(input != null && !(input.equalsIgnoreCase("exit"))){
System.out.print("New input: ");
System.out.println(input);
out.println(input);
out.flush();
} else if(input.equalsIgnoreCase("exit")){
disconnect();
}
}
}
} catch(SocketException e) {
disconnect();
} catch (IOException e) {
e.printStackTrace();
return;
}
}
public void disconnect(){
System.out.println("Client " + num + " disconnected!");
out.close();
try {
in.close();
cltSocket.close();
} catch (IOException e) {
e.printStackTrace();
}
}
}
MessageClient.java
import java.net.*;
import java.io.*;
public class MessageClient {
public static void main(String[] args) {
if(args.length != 2) {
System.out.println("Invalid parameters! Format as: (hostname) (port)");
System.exit(1);
}
String hostname = args[0];
int port = Integer.parseInt(args[1]);
try {
Socket socket = new Socket(hostname, port);
PrintWriter out = new PrintWriter(socket.getOutputStream(), true);
BufferedReader in = new BufferedReader(new InputStreamReader(socket.getInputStream()));
BufferedReader con = new BufferedReader(new InputStreamReader(System.in));
System.out.println("Connected!");
while(socket.isConnected() && !socket.isClosed()){
String output;
if(con.ready()) {
output = con.readLine();
out.println(output);
if(output.equalsIgnoreCase("exit")) {
socket.close();
}
}
if(in.ready()){
String li = in.readLine();
if(li != null) {
System.out.println(li);
}
}
}
System.out.println("Disconnected!");
con.close();
out.close();
in.close();
System.exit(0);
} catch(SocketException e) {
System.err.println("Socket error:" + e);
} catch(UnknownHostException e) {
System.err.println("Invalid host");
} catch(IOException e) {
System.err.println("IO Error: " + e);
}
}
}
如果你讀的InputStream和對方插座走的方式,然後你會得到一個例外......這是一種檢查丟失連接的方法 –
哇。我刪除了'if(in.ready())'檢查,並且它完美地工作。非常感謝! – user3433131