如果沒有互聯網連接,你按下按鈕來觸發某些事件,檢查UIWebViewDelegate
方法稱爲didFailWithError
:
- (void)webView:(UIWebView *)webView didFailLoadWithError:(NSError *)error {
//Check the error type and show the appropriate alert to user.
}
,當你正在使用PhoneGap的,你總是可以先檢查網絡連接通過使用Connection API發射任何負載請求之前:
<!DOCTYPE html>
<html>
<head>
<title>navigator.connection.type Example</title>
<script type="text/javascript" charset="utf-8" src="cordova-2.2.0.js"></script>
<script type="text/javascript" charset="utf-8">
document.addEventListener("deviceready", onDeviceReady, false);
function onDeviceReady() {
//checkConnection();
}
function checkConnection() {
var networkState = navigator.connection.type;
var states = {};
states[Connection.UNKNOWN] = 'Unknown connection';
states[Connection.ETHERNET] = 'Ethernet connection';
states[Connection.WIFI] = 'WiFi connection';
states[Connection.CELL_2G] = 'Cell 2G connection';
states[Connection.CELL_3G] = 'Cell 3G connection';
states[Connection.CELL_4G] = 'Cell 4G connection';
states[Connection.NONE] = 'No network connection';
alert('Connection type: ' + states[networkState]);
if(networkState==Connection.NONE)
return false;
else
return true;
}
function loadGoogle() {
if(checkConnection()){
// Do your logical stuff here
window.location="https://google.com";
}
else {
// Handle connection error
}
}
</script>
</head>
<body>
<p>A dialog box will report the network state.</p>
<button onclick="loadGoogle()">Load Google</button>
</body>
</html>
didFailWithError也沒有觸發,並使用HTML是沒辦法了。假設html在webview上正確加載並且具有觸發事件onClick的按鈕,那麼我將禁用設備上的Internet連接。現在點擊時,我必須捕捉任何事件以檢查互聯網連接。但交互狀態在conn check之前。 – Jaume