枚舉綁定組合框中選擇的值設置爲枚舉值

Question

有一個在我的項目像這樣的枚舉：

public enum UserFrienlyEnum 
{ 
    [Description("it need spec training")] 
    SPECIAL_TRAINING = 1, 
    [Description("it need normal training")] 
    NORMAL_TRAINING = 2, 
    [Description("it need simple training")] 
    SIMPLE_TRAINING = 3 
} 

我用這種方法束縛，這枚舉組合框：

public static void setEnumValues(ComboBox cxbx, Type typ) 
{ 
    if (!typ.IsEnum) 
    { 
     throw new ArgumentException("Only Enum types can be set"); 
    } 

    List<KeyValuePair<string, int>> list = new List<KeyValuePair<string, int>>(); 

    foreach (int i in Enum.GetValues(typ)) 
    { 
     string name = Enum.GetName(typ, i); 
     string desc = name; 
     FieldInfo fi = typ.GetField(name); 

     // Get description for enum element 
     DescriptionAttribute[] attributes = (DescriptionAttribute[])fi.GetCustomAttributes(typeof(DescriptionAttribute), false); 

     if (attributes.Length > 0) 
     { 
      string s = attributes[0].Description; 

      if (!string.IsNullOrEmpty(s)) 
      { 
       desc = s; 
      } 
     } 

     list.Add(new KeyValuePair<string, int>(desc, i)); 
    } 
    // NOTE: It is very important that DisplayMember and ValueMember are set before DataSource. 
    //  If you do, this works fine, and the SelectedValue of the ComboBox will be an int 
    //  version of the Enum. 
    //  If you don't, it will be a KeyValuePair. 
    cxbx.DisplayMember = "Key"; 
    cxbx.ValueMember = "Value"; 
    cxbx.DataSource = list; 
} 

並使用以上方法將combobox綁定到myEnum中：

setEnumValues(comboBox, typeof(myEnum)); 

現在問題是如何設置我的組合框項目或值到特定的一個，如下所示：

combobox.SelectedValue = myEnum.value; 

我的項目是在Visual Studio 2010環境中的C＃windows項目。

Answer 1

我複製了你的代碼，我認爲這是你的，這對我來說工作得很好。

namespace WindowsFormsApplication1 
{ 
    public class MyClass 
    { 
     public string Something { get; set; } 
     public UserFrienlyEnum foo { get; set; } 
    } 
    public enum UserFrienlyEnum 
    { 
     [Description("it need spec training")] 
     SPECIAL_TRAINING = 1, 
     [Description("it need normal training")] 
     NORMAL_TRAINING = 2, 
     [Description("it need simple training")] 
     SIMPLE_TRAINING = 3 
    } 
    public partial class Form1 : Form 
    { 


     private void Form1_Load(object sender, EventArgs e) 
     { 
      setEnumValues(this.comboBox1, typeof(UserFrienlyEnum)); 
      MyClass variable = new MyClass(); 
      variable.foo = UserFrienlyEnum.NORMAL_TRAINING; 
      this.comboBox1.SelectedValue = (int)variable.foo; 

     } 

     public static void setEnumValues(ComboBox cxbx, Type typ) 
     { 
      if (!typ.IsEnum) 
      { 
       throw new ArgumentException("Only Enum types can be set"); 
      } 

      List<KeyValuePair<string, int>> list = new List<KeyValuePair<string, int>>(); 

      foreach (int i in Enum.GetValues(typ)) 
      { 
       string name = Enum.GetName(typ, i); 
       string desc = name; 
       FieldInfo fi = typ.GetField(name); 

       // Get description for enum element 
       DescriptionAttribute[] attributes = (DescriptionAttribute[])fi.GetCustomAttributes(typeof(DescriptionAttribute), false); 
       if (attributes.Length > 0) 
       { 
        string s = attributes[0].Description; 
        if (!string.IsNullOrEmpty(s)) 
        { 
         desc = s; 
        } 
       } 

       list.Add(new KeyValuePair<string, int>(desc, i)); 
      } 
      // NOTE: It is very important that DisplayMember and ValueMember are set before DataSource. 
      //  If you do, this works fine, and the SelectedValue of the ComboBox will be an int 
      //  version of the Enum. 
      //  If you don't, it will be a KeyValuePair. 
      cxbx.DisplayMember = "Key"; 
      cxbx.ValueMember = "Value"; 
      cxbx.DataSource = list; 
     } 

     public Form1() 
     { 
      InitializeComponent(); 
     } 


    } 
} 

結果：

Answer 2

感謝我的朋友Hanlet這是最簡單的答案：

combobox.SelectedValue = (int) myEnum.value; 

鑄造它爲int是關鍵。