上傳mp4文件

Question

我想用php上傳mp4文件，並且我成功了，但之後，文件無法用VLC運行，即使它可以在上傳之前運行。該錯誤消息說，該文件無法打開給我的文件的路徑，並以（壞文件描述符）結束。 我做了在php.ini文件中的以下配置：

file_uploads = On 
upload_max_filesize = 25M 
post_max_size = 25M 

這裏是我的代碼：

if ($_FILES["video"]["name"] == "") { 
    $error = "No video imported."; 
    } 
    else { 
    if (file_exists("uploads/" . $_FILES["video"]["name"])) { 
     $error = "The file already exists."; 
    } 
    else if ($_FILES["video"]["type"] != "video/mp4") { 
     $error = "File format not supported."; 
    } 
    else if ($_FILES["video"]["size"] > 26214400) { 
     $error = "Only files <= 25ΜΒ."; 
    } 
    else { 
     move_uploaded_file($_FILES["video"]["tmp_name"], "uploads/" . $_FILES["video"]["name"]); 
    } 
    } 

<form action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]); ?>" method="post" enctype="multipart/form-data"> 
    <fieldset> 
     <div class="area"> 
     <label for="path">Select file:</label> 
      <input class="upload" type="file" name="video"></input> 
      <span><?php echo $error; ?></span><br /> 
     </div> 
    </fieldset> 

    <input type="submit" name="insert" value="upload"></input> 
</form> 

Answer 1

你對線4 & 5.語法錯誤，它應該是

} elseif (file_exists("uploads/" . $_FILES["video"]["name"])) { 

不：

} else { 
    if (file_exists("uploads/" . $_FILES["video"]["name"])) { 

此代碼已經過測試並正在運行。

<?php 
if ($_FILES["video"]["name"] == "") { 
    $error = "No video imported."; 
} elseif (file_exists("uploads/" . $_FILES["video"]["name"])) { 
    $error = "The file already exists."; 
} elseif ($_FILES["video"]["type"] != "video/mp4") { 
    $error = "File format not supported."; 
} elseif ($_FILES["video"]["size"] > 26214400) { 
    $error = "Only files <= 25??."; 
} else { 
    move_uploaded_file($_FILES["video"]["tmp_name"], "uploads/" . $_FILES["video"]["name"]); 
} 

?> 
<form action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]); ?>" method="post" enctype="multipart/form-data"> 
    <fieldset> 
     <div class="area"> 
     <label for="path">Select file:</label> 
      <input class="upload" type="file" name="video"></input> 
      <span><?php echo $error; ?></span><br /> 
     </div> 
    </fieldset> 

    <input type="submit" name="insert" value="upload"></input> 
</form>