2012-06-30 46 views
3

我想在我當前的rails應用程序上設置基於json的身份驗證。應用程序的身份驗證目前由devise處理。Json身份驗證到設計

我已經閱讀了幾個關於stackoverflow的問題,但我似乎沒有得到它的工作。

的routes.rb:

devise_for :users, :controllers => { :omniauth_callbacks => "users/omniauth_callbacks", :sessions => 'users/sessions' } 

SessionsController:

class Users:: SessionsController < Devise::SessionsController 
    def create 
    resource = warden.authenticate!(:scope => resource_name, :recall => :failure) 
    return sign_in_and_redirect(resource_name, resource) 
    end 

    def sign_in_and_redirect(resource_or_scope, resource=nil) 
    scope = Devise::Mapping.find_scope!(resource_or_scope) 
    resource ||= resource_or_scope 
    sign_in(scope, resource) unless warden.user(scope) == resource 
    return render :json => {:success => true, :redirect => stored_location_for(scope) || after_sign_in_path_for(resource)} 
    end 

    def failure 
    return render:json => {:success => false, :errors => ["Login failed."]} 
    end 
end 

不知道在那裏我已經錯了。我想提出的調用是:

JSON:

Content-Type: application/json 
Accept: application/json 
data: {user: {password: mypass, email: [email protected]}} 

的錯誤:

MultiJson::DecodeError (756: unexpected token at '{user: {password: mypass, email: [email protected]}}'): 
2012-06-30T18:10:10+00:00 app[web.1]: vendor/bundle/ruby/1.9.1/gems/json-1.6.5/lib/json/common.rb:148:in `parse' 

回答

1

如果粘貼成JSON http://jsonlint.com,你得到同樣的錯誤..相反,您應該將您的值包含在引號中:

{ 
    "user": { 
     "password": "mypass", 
     "email": "[email protected]" 
    } 
} 
+0

稍微偏離主題 - 當登錄失敗時,返回值不是json失敗 - 而是返回html根頁面。任何想法爲什麼? – Karan

+1

@Newton我在這裏寫了類似的文章:http://jessewolgamott.com/blog/2012/01/19/the-one-with-a-json-api-login-using-devise/ –

+0

真棒,謝謝傑西! – Karan