共享對象和包含沒有安裝在Linux下的C++

Question

我在寫一個程序，它有兩個我需要使用的庫：v8和v8-juice。不幸的是，v8-juice不能被編譯爲一個靜態庫，因爲它使用了模板。還有一些需要將v8編譯爲共享對象的怪癖。

所以，當我編譯我的程序時，最終有兩個可執行文件需要運行的共享對象。我的問題是，有沒有一種方法可以包含這些共享對象，而無需在Linux下進行安裝？對不起，如果這是一個新手問題，我對C++來說還很陌生。

Answer 1

共享庫可以與您的可執行文件位於同一個文件夾中。 man ld.so：

$ORIGIN and rpath 

    ld.so understands the string $ORIGIN (or equivalently ${ORIGIN}) in an 
    rpath specification (DT_RPATH or DT_RUNPATH) to mean the directory con- 
    taining the application executable. Thus, an application located in 
    somedir/app could be compiled with gcc -Wl,-rpath,'$ORIGIN/../lib' so 
    that it finds an associated shared library in somedir/lib no matter 
    where somedir is located in the directory hierarchy. This facilitates 
    the creation of "turn-key" applications that do not need to be 
    installed into special directories, but can instead be unpacked into 
    any directory and still find their own shared libraries.