PHP在做str_replace函數功能失常更換

Question

嗯，我編寫一個PHP函數用於多個字符串替換

$searchArray = array("0","9","8","7","6","5","4","3","2","1","!","@","#","$","%","^","&","*","(",")","z","x","y","w","u","v","j","i","h","g","f","e","d","c","b","a"); 
$replaceArray = array("1","2","3","4","5","6","7","8","9","0","a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z");  
$string='protect your php code'; 
echo $code=str_replace($searchArray, $replaceArray, $string); 

其結果= protvxt沼地PSP xowv

很好，當我改變其位置，這似乎正確

$string='protvxt moor psp xowv';  
$searchArray = array("1","2","3","4","5","6","7","8","9","0","a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"); 

$replaceArray = array("0","9","8","7","6","5","4","3","2","1","!","@","#","$","%","^","&","*","(",")","z","x","y","w","u","v","j","i","h","g","f","e","d","c","b","a"); 
echo $code=str_replace($searchArray, $replaceArray, $string); 

它給了我這個答案= eifgecg bffi ehe cfde（這是錯誤的）它應該正確顛倒並給出答案保護你的php代碼

老實說，我不知道爲什麼PHP這樣做不對

我粘貼以上代碼在這裏

http://codepad.org/xbSCieZl 

請這個我想知道我做錯了這讓我很惱火

Answer 1

你的陣列應該包含相同的字符。

第一轉換不會改變從「保護」

字符「親」，但倒車呢。

編輯：
對不起，這個答案是錯誤的，因爲我沒有意識到下面的問題，詹姆斯上面提到：「這一般不會工作，你的測試字符串很幸運，如果你嘗試編碼字符串「123」你會得到「123」，因爲1變成了零，然後在零後面變成1等，看看str_replace gotchas - James「

你可以使用上面的建議strtr函數的效率（）

$search = "abcdefghijklmnopqrstuvwxyz"; 
$replace = "zabcdefghijklmnopqrstuvwxy"; 

$string='protect your php code'; 

echo $code=strtr($string, $search, $replace); 
echo '<br>';  
echo strtr($code, $replace, $search); 

輸出：
oqnsdbs xntq奧戈bncd
保護你的PHP代碼

編輯：
還可以生成您的字符串和隨機：

$search = implode("",range("a","z")).implode("",range("0","9")); 
$replace = str_shuffle($search); 

http://codepad.org/DZJRp9Zx