使用bash逐行讀取文件，提取一些數據。怎麼樣？

Question

我想根據某個標籤從文件中讀取摘錄信息。例如：

SCRIPT_NAME:mySimpleShell.sh 

This is a simple shell. I would like to have this as 
Description. I also want to create a txt file our of this. 

SCRIPT_NAME:myComplexShell.sh 

This is a complex shell. I would like to have this as 
Description. I also want to create a txt file our of this. 

所以，當我通過這個文件，以我的shell腳本，我的shell會逐行閱讀並 當它到達SCRIPT_NAME，它提取它，並將它保存在$ FILE_NAME，然後開始使用$ FILE_NAME.txt名稱將 描述寫入磁盤上的文件。直到達到文件末尾。如果有3個SCRIPT_NAME標記，則它會創建3個描述文件。

謝謝你幫我提前:)

Answer 1

使用while循環讀取線。使用正則表達式來檢查一行是否有SCRIPT_NAME，如果是，提取文件名。這顯示如下：

#! /bin/bash 
while IFS= read -r line 
do 
    if [[ $line =~ SCRIPT_NAME:(.*$) ]] 
    then 
     FILENAME="${BASH_REMATCH[1]}" 
     echo "Writing to $FILENAME.txt" 
    else 
     echo "$line" >> "$FILENAME.txt" 
    fi 
done < inputFile 

Answer 2

#!/bin/sh 

awk '/^SCRIPT_NAME:/ { split($0, a, ":"); name=a[2]; next } 
    name { print > name ".txt" }' ${1?No input file specified}