通過陣列與另一個陣列進行過濾

Question

我正在嘗試使用React JS創建搜索。

我有一個數組（汽車），我想通過它搜索。我有一個過濾器陣列（在這種情況下是一個），我需要應用。最後，我擁有該過濾器的內容。

我有這樣三個數組對象：

• 汽車（全車的列表）。它看起來如下：

  let cars = [ 
      {"id":20,"listID":3,"make":"Golf"}, 
      {"id":21,"listID":3,"make":"Passat"}, 
      {"id":22,"listID":3,"make":"Audi"}, 
      {"id":23,"listID":3,"make":"Touran"}, 
      {"id":24,"listID":3,"make":"Touran"} 
  ]; 
  

• 過濾器（陣列的所有過濾器 - 在這種情況下，只有一個過濾器）：

  let filters = [ 
       {"name":"FAVORITES","values":[  
             {"carID":21,"listID":3,"userID":12}, 
             {"carID":22,"listID":3,"userID":12} 
            ] 
       } 
  ]; 
  

• 夾（即過濾器的內容）：

  let favorites = [ 
      {"carID":21,"listID":3,"userID":12}, 
      {"carID":22,"listID":3,"userID":12} 
  ]; 
  

渲染功能如下：

render(){ 
    return cars.filter(car => filters.every(filter => filterItem(filter, car))) 
} 

因此，我過濾所有的汽車，應用每個過濾器，然後調用每個汽車和每個過濾器的filterItem函數。

和功能的FilterItem（這裏我想要得到的結果）如下：

function filterItem(filter, car) { 
    switch(filter.name) { 
     case "FAVORITES": 
       return filter.values.map(f => f).every(v => car.id === v.carID && car.listID === v.listID); 
     default: 
      return true; 
    } 
} 

這一切都在一個部件結合：

let favorites = [ 
    {"carID":21,"listID":3,"userID":12}, 
    {"carID":22,"listID":3,"userID":12} 
]; 


let cars = [ 
    {"id":20,"listID":3,"make":"Golf"}, 
    {"id":21,"listID":3,"make":"Passat"}, 
    {"id":22,"listID":3,"make":"Audi"}, 
    {"id":23,"listID":3,"make":"Touran"}, 
    {"id":24,"listID":3,"make":"Touran"} 
]; 

let filters = [ 
    {"name":"FAVORITES","values":[ 
           {"carID":21,"listID":3,"userID":12},  
           {"carID":22,"listID":3,"userID":12} 
           ] 
    } 
] 

function filterItem(filter, car) { 
    switch(filter.name) { 
     case "FAVORITES": 
      return filter.values.map(f => f).every(v => car.id === v.carID && car.listID === v.listID); 
     default: 
      return true; 
    } 
} 

class Test extends React.Component { 
    render(){ 
     return (
     <div> 
      {cars.filter(car => filters.every(filter => filterItem(filter, car)))} 
     </div> 
    ) 
    } 
} 

React.render(<Test />, document.getElementById('container')); 

因此我想通過汽車搜索，並應用所有過濾器（在這種情況下只有一個）並獲得結果。

因此，在這種情況下，結果應該是：

let results = [ 
    {"id":21,"listID":3,"make":"Passat"}, 
    {"id":22,"listID":3,"make":"Audi"} 
] 

但是我的代碼我什麼也沒得到。

有什麼建議嗎？

Here is fiddle.

Answer 1

你問如果一個car對象匹配的值的every在filter，它做不到的。你想寫的是什麼，我認爲是some。 some檢查過濾器中是否有匹配的值之一。例如：

let favorites = [ 
 
    {"carID":21,"listID":3,"userID":12}, 
 
    {"carID":22,"listID":3,"userID":12} 
 
]; 
 

 

 
let cars = [ 
 
    {"id":20,"listID":3,"make":"Golf"}, 
 
    {"id":21,"listID":3,"make":"Passat"}, 
 
    {"id":22,"listID":3,"make":"Audi"}, 
 
    {"id":23,"listID":3,"make":"Touran"}, 
 
    {"id":24,"listID":3,"make":"Touran"} 
 
]; 
 

 
let filters = [ 
 
    {"name":"FAVORITES","values":[ 
 
     {"carID":21,"listID":3,"userID":12},  
 
     {"carID":22,"listID":3,"userID":12} 
 
    ] 
 
    } 
 
] 
 

 
function filterItem(filter, car) { 
 
    switch(filter.name) { 
 
     case "FAVORITES": 
 
      return filter 
 
       .values 
 
      // Here, we change `every` to `some`, since a car has to match only ONE value 
 
       .some(v => car.id === v.carID && car.listID === v.listID); 
 
     default: 
 
      return true; 
 
    } 
 
} 
 

 
var favFilter = filterItem.bind(null, filters[0]); 
 
var filteredCars = cars.filter(favFilter); 
 
console.log(filteredCars);