1
所以我不能添加一個隨機索引來傳遞我i [x] = pass [rand.nextInt(pass.size())];如何添加兩個char []到列表<Object>?
char[] azL = {'a', 'b', 'c'};
char[] nzL = {'0', '1', '2'};
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
initializeValues();
cha();
but.setOnClickListener(new View.OnClickListener() {
int Plength = 6;
char[] i = new char[Plength];
List<Object> pass = new ArrayList<>();
@Override
public void onClick(View v) {
for (int x = 0; x < Plength; x++) {
i[x] = pass[rand.nextInt(pass.size())];
}
textV.setText(String.valueOf(i));
}
});
}
public void cha() {
List<Object> pass = new ArrayList<>();
pass.add(azL[rand.nextInt(azL.length)]);
pass.add(nzL[rand.nextInt(azL.length)]);
}
它說: 「預計數組類型;發現:「java.util.List的」,我不知道該怎麼do..please幫助