XPath或Defiant.js和獲取節點信息

Question

我有我的JSON：

{ 
    "data": { 
    "header": { 
     "version": 1, 
     "last_updated": "2015-09-16T14:09:22Z" 
    }, 
    "frequent" : { 
     "keywords": [ 
     { 
      "keyword":"roi", 
      "keyword":"subjectrecord", 
      "keyword":"evidence", 
      "keyword":"case", 
      "keyword":"account", 
      "keyword":"supervisor", 
      "keyword":"legacy tecs" 
     } 
     ] 
    }, 
    "body": { 
     "items": [ 
     { 
      "item": { 
      "type": "pdf", 
      "title": "title 1", 
      "updated_time": "2015-09-16T14:09:22Z", 
      "keywords": [ 
       { 
       "keyword":"supervisor" 
       }, 
       { 
       "keyword":"manager" 
       }, 
       { 
       "keyword":"title 1" 
       } 
      ] 
      } 
     }, 
     { 
      "item": { 
      "type": "pdf", 
      "title": "title 2", 
      "updated_time": "2015-09-16T14:09:22Z", 
      "keywords": [ 
       { 
       "keyword":"supervisor" 
       } 
      ] 
      } 
     }, 
     { 
      "item": { 
      "type": "pdf", 
      "title": "title 3", 
      "updated_time": "2015-09-16T14:09:22Z" 
      } 
     } 
     ] 
    } 
    } 
} 

什麼，我希望能夠做的是搜索「身體」，回到哪裏與之匹配的關鍵字出現的任何項目。因此，舉例來說，如果我搜索「監督員」我的結果應該是這樣的：

"item": { 
     "type": "pdf", 
     "title": "title 1", 
     "updated_time": "2015-09-16T14:09:22Z", 
     "keywords": [ 
      { 
      "keyword":"supervisor" 
      }, 
      { 
      "keyword":"manager" 
      }, 
      { 
      "keyword":"title 1" 
      } 
     ] 
     } 
    }, 
    { 
     "item": { 
     "type": "pdf", 
     "title": "title 2", 
     "updated_time": "2015-09-16T14:09:22Z", 
     "keywords": [ 
      { 
      "keyword":"supervisor" 
      } 
     ] 
     } 
    } 

執行以下操作，只返回關鍵字。

var results = JSON.search(potentials, '//*[keyword="'+query+'"]'); 

Answer 1

看跌/ ..在查詢結束

var results = JSON.search(potentials, '//*[keyword="'+query+'"]/..');