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我目前有問題產生,因爲我不使用PHP的那麼多,但任何人都可以幫助我建立JSON象下面這樣的JSON響應:如何在php中添加對象內的對象?
{
"set_attributes":
{
"apikey": "some value",
},
"block_names": ["getdata"],
"type": "show_block",
"title": "go"
}
這裏是我的代碼:
$response = array();
$response['block_names'] = array();
$response['block_names'] = "getdata";
$response['type'] = "show_block";
$response['title'] = "go";
if ($db->studentLogin($username, $password)) {
$student = $db->getStudent($username);
$temp = array();
$temp['apikey'] = $student['api_key'];
$response['set_attributes'] = $temp['apikey'];
} else {
$temp = array();
$response['messages'] = array();
$temp['text'] = "Invalid username or password";
array_push($response['messages'],$temp);
}
echoResponse(200, $response);
這表明像這樣:
{
"block_names": "getdata",
"type": "show_block",
"title": "go",
"set_attributes": "f74911b29778adea86aa24d5ce85ff58"
}
但我想補充apikey = 「f74911b29778adea86aa24d5ce85ff58」 內set_attributes和[]外block_names就像obove。我怎樣才能做到這一點?
'$迴應[ 'set_attributes'] = $溫度;' - 現在你需要正義價值 – splash58
'$迴應[ 'block_names'] =陣列(」的GetData「);' – splash58