解析XML和PHP中

Question

讀取每個元素我從一個API的XML輸出以下

<?xml version='1.0' encoding='UTF-8'?> 
<Response> 
    <ReturnRow Output1="11" Output2="12" Output3="13" Output4="14" Output5="15" /> 
    <ReturnRow Output1="21" Output2="22" Output3="23" Output4="24" Output5="25" /> 
    <Messages> 
     <Message Code="INFO" Msg="Your request is successful." Type="APP"/> 
    </Messages>  
</Response> 

我試圖解析使用PHP上面的XML，環子元素ReturnRown和回聲出Output1， Output2轉換成HTML表格。

這裏是我的代碼目前：

$doc = new DOMDocument(); 
$doc->loadXML($test); //$test is holding the above XML 
$node = $doc->getElementsByTagName("ReturnRow"); 
foreach ($node as $book) { 
    var_dump($book); 
} 

但上面沒有實際給我的價值觀Ouput1，Output2等

我缺少什麼或者做錯了嗎？

的我上面的PHP代碼的結果是：

object(DOMElement)#3 (18) { ["tagName"]=> string(9) "ReturnRow" ["schemaTypeInfo"]=> NULL  ["nodeName"]=> string(9) "ReturnRow" ["nodeValue"]=> string(0) "" ["nodeType"]=> int(1)  ["parentNode"]=> string(22) "(object value omitted)" ["childNodes"]=> string(22) "(object value omitted)" ["firstChild"]=> NULL ["lastChild"]=> NULL ["previousSibling"]=> string(22) "(object value omitted)" ["nextSibling"]=> string(22) "(object value omitted)" ["attributes"]=> string(22) "(object value omitted)" ["ownerDocument"]=> string(22) "(object value omitted)" ["namespaceURI"]=> NULL ["prefix"]=> string(0) "" ["localName"]=> string(9) "ReturnRow" ["baseURI"]=> string(20) "file:///W:/ischools/" ["textContent"]=> string(0) "" } object(DOMElement)#5 (18) { ["tagName"]=> string(9) "ReturnRow" ["schemaTypeInfo"]=> NULL ["nodeName"]=> string(9) "ReturnRow" ["nodeValue"]=> string(0) "" ["nodeType"]=> int(1) ["parentNode"]=> string(22) "(object value omitted)" ["childNodes"]=> string(22) "(object value omitted)" ["firstChild"]=> NULL ["lastChild"]=> NULL ["previousSibling"]=> string(22) "(object value omitted)" ["nextSibling"]=> string(22) "(object value omitted)" ["attributes"]=> string(22) "(object value omitted)" ["ownerDocument"]=> string(22) "(object value omitted)" ["namespaceURI"]=> NULL ["prefix"]=> string(0) "" ["localName"]=> string(9) "ReturnRow" ["baseURI"]=> string(20) "file:///W:/ischools/" ["textContent"]=> string(0) "" } 

Answer 1

在你的情況，我寧願用simplexml，因爲它可以返回一個節點的所有屬性在容易迭代格式，並使用XPath找到您是節點興趣：

$xml = '<'.'?xml version="1.0" encoding="UTF-8"?> 
<Response> 
    <ReturnRow Output1="11" Output2="12" Output3="13" Output4="14" Output5="15" /> 
    <ReturnRow Output1="21" Output2="22" Output3="23" Output4="24" Output5="25" /> 
    <Messages> 
     <Message Code="INFO" Msg="Your request is successful." Type="APP"/> 
    </Messages> 
</Response> 
'; 

$doc = simplexml_load_string($xml); 
$node = $doc->xpath('//ReturnRow'); 
foreach ($node as $book) { 
    foreach ($book->attributes() as $name => $value) { 
     var_dump((string)$name, (string)$value); 
    } 
} 

如果你的輸入一直有這些屬性可以使用的DOMNode的getAttribute()方法在你的原始代碼的循環以獲得的值：

foreach ($node as $book) { 
    var_dump($book->getAttribute('Output1'), $book->getAttribute('Output2')); 
}