嚴格的標準：只有變量應該通過參考請

Question

嚴格的標準進行傳遞：在請只變量應該按引用傳遞

if(isset($_FILES['image'])){ 
    $errors= array(); 
    $file_name = $_FILES['image']['name']; 
    $file_size =$_FILES['image']['size']; 
    $file_tmp =$_FILES['image']['tmp_name']; 
    $file_type=$_FILES['image']['type']; 
    $file_ext=strtolower(end(explode('.',$_FILES['image']['name']))); 

    $expensions= array("jpeg","jpg","png","docx","pdf"); 

    if(in_array($file_ext,$expensions)=== false){ 
    $errors="<div align='center'><font color='red'>extension not allowed, please choose a JPEG or PNG file.</font></div>"; 
    } 

Answer 1

內置end預計按引用傳遞的數組。所以傳遞的數組必須是一個變量。

$var = explode('.',$_FILES['image']['name']); 
    $file_ext=strtolower(end($var)); 

This means you must pass it a real variable and not a function returning an array