從jQuery選擇中刪除沒有ID的元素？

Question

如何從插件被調用的集合（不是DOM本身）中移除沒有id屬性的元素？

<span id="id737293" class="attach"></span> 
<div class="attach"></span> 

jQuery的調用和插件：

$('.attach').attach(); 

(function($) { 

    $.fn.attach = function(options) { 
     // Remove elements (without id) on which the plugin was invoked 
     var valid = ???; 

     // Loop each valid element (with id attribute) and process 
     valid.each(function() { 
     }); 

     return this; // Maintain chainability 
    }; 

})(jQuery); 

Answer 1

.filter使用刪除元素沒有ID。

(function($) { 

    $.fn.attach = function(options) { 
     // Remove elements (without id) on which the plugin was invoked 
     var valid = this.filter(function() { return !!this.id; }); 

     // Loop each valid element (with id attribute) and process 
     valid.each(function() {    
     }); 

     return this; // Maintain chainability 
    }; 

})(jQuery); 

$('.attach').attach(); 

http://jsfiddle.net/5Kn9W/2/

或var valid = this.not(':not([id])'); - http://jsfiddle.net/5Kn9W/1/

Answer 2

if(!$(elem).prop("id")){ 
    $(this).remove() 
} 

Answer 3

var elementsWithClassAttachAndHasId = jQuery(".attach:has([id])"); 
var elementsWithClassAttachAndNoId = jQuery(".attach:not([id])");