grep返回整個對象，而不是數組

Question

有什麼辦法可以強制jQuery的grep函數返回新的對象與反射的新數組？例如，我有如下樣本JSON和JavaScript。

var myObject = {  "Apps" : [  
    { 
     "Name" : "app1", 
     "id" : "1", 
     "groups" : [ 
      { "id" : "1", 
       "name" : "test group 1", 
       "desc" : "this is a test group" 
      }, 
      { "id" : "2", 
       "name" : "test group 2", 
       "desc" : "this is another test group" 
      }, 
       { "id" : "2", 
       "name" : "test group 2", 
       "desc" : "this is another test group" 
      } 
     ]    
    } 
    ] 
    } 

var b,a; 
    $.each(myObject.Apps, function() {  
    b = $.grep(this.groups, function(el, i) { 
    return el.id.toLowerCase() === "2"     
    });   

    }); 

alert(JSON.stringify(b)); 

所以一旦我運行這個，我會得到如下預警的文本。

[{"id":"2","name":"test group 2","desc":"this is another test group"},{"id":"2","name":"test group 2","desc":"this is another test group"}] 

但我想這個新的返回數組這樣的整個javascript對象。 預期的O/P ::

"Apps" : [  
    { 
     "Name" : "app1", 
     "id" : "1", 
     "groups" : [ 
      { "id" : "2", 
       "name" : "test group 2", 
       "desc" : "this is another test group" 
      }, 
       { "id" : "2", 
       "name" : "test group 2", 
       "desc" : "this is another test group" 
      } 
     ]    
    } 
    ] 

任何想法將是一個很大的幫助。

Answer 1

如果理解正確，您希望從主對象中刪除任何未在$ .grep中返回的組。

使用您$.grep()方法在$.each循環後$.grep

DEMO添加一行：http://jsfiddle.net/67Bbg/

var b,a; 
$.each(myObject.Apps, function() {  
    b = $.grep(this.groups, function(el, i) { 
     return el.id.toLowerCase() === "2"     
    }); 

    /* replace group with new array from grep */   
    this.groups=b; 
}); 

編輯：簡化版本

$.each(myObject.Apps, function() {  
    this.groups= $.grep(this.groups, function(el, i) { 
     return el.id.toLowerCase() === "2"     
    }); 
});