如何在Rally .NET Web服務API中的Epic下獲取所有缺陷

Question

我正在使用RallyRestToolkitFor.NET編寫應用程序。我能夠爲特定工作區的所有用戶素材提取列出的字段。現在我想根據特定的「史詩」來獲取故事。我無法找到在文檔鏈接中執行此操作的方式。

我想知道是否有可能嘗試去做。如果答案是肯定的，請告訴我方式。鏈接或示例代碼或指針，我感謝任何幫助。

謝謝，薩加爾。

Answer 1

這裏是獲取一個特定的史詩故事代碼：

namespace FindChildren 
{ 
    class Program 
    { 
     static void Main(string[] args) 
     { 
      RallyRestApi restApi; 
      restApi = new RallyRestApi("user@co.com", "secret", "https://rally1.rallydev.com", "v2.0"); 

      String projectRef = "/project/12352814790";  //replace this OID with an OID of your project 

      Request sRequest = new Request("HierarchicalRequirement"); 
      sRequest.Project = projectRef; 
      sRequest.Fetch = new List<string>() { "FormattedID", "Name", "Children" }; 
      sRequest.Query = new Query("FormattedID", Query.Operator.Equals, "US384"); 
      QueryResult queryResults = restApi.Query(sRequest); 

      foreach (var s in queryResults.Results) 
      { 
       Console.WriteLine("FormattedID: " + s["FormattedID"] + " Name: " + s["Name"]); 
       Console.WriteLine("Collection ref: " + s["Children"]._ref); 
       Request childrenRequest = new Request(s["Children"]); 
       QueryResult queryChildrenResult = restApi.Query(childrenRequest); 
       foreach (var c in queryChildrenResult.Results) 
       { 
        Console.WriteLine("FormattedID: " + c["FormattedID"] + " Name: " + c["Name"]); 
       } 

      } 
     } 
    } 
}