2017-04-30 63 views
0

我對jQuery非常陌生,遇到了一些麻煩。我的項目使用表單登錄/註冊頁面,並且僅限於使用localStorage。當我運行該項目時,就好像登錄和註冊的提交按鈕被混淆了,儘管它們具有不同的id標籤。我很困惑,我知道這個問題可能非常愚蠢,但我一直在尋找幾個小時,無法修復它。任何幫助,將不勝感激!查詢混淆提交按鈕

的html代碼:

<!DOCTYPE html> 
<html> 
<head> 
<meta name="viewport" content="width=device-width, initial-scale=1"> 
<link rel="stylesheet" href="https://code.jquery.com/mobile/1.4.5/jquery.mobile-1.4.5.min.css"> 
<script src="https://code.jquery.com/jquery-1.11.3.min.js"></script> 
<script src="https://code.jquery.com/mobile/1.4.5/jquery.mobile-1.4.5.min.js"></script> 
<script type="text/javascript" src="welcome.js"></script> 
</head> 
<body> 

<div data-role="page"> 
    <div data-role="header"> 
<h1>My Calendar</h1> 
    </div> 

    <div data-role="main" class="ui-content"> 
    <a href="#myPopup" data-rel="popup" class="ui-btn ui-btn-inline ui-btn-b ui-corner-all">Sign-in</a> 

<div data-role="popup" id="myPopup" class="ui-content" style="min-width:250px;"> 

    <form method="post" action=" "> 
    <div class="ui-field-contain"> 
    <label for="fullname">Full name:</label> 
    <input type="text" name="fullname" id="fullname">  

    <label for="email">E-mail:</label> 
    <input type="email" name="email" id="email" placeholder="Your email.."> 
    </div> 
    <input id="submit" type="submit" data-inline="true" value="Submit"> 
</form> 
</div> 
    </div> 


    <div data-role="main" class="ui-content"> 
<a href="#myPopup1" data-rel="popup" class="ui-btn ui-btn-inline ui-btn-b ui-corner-all">Sign-up</a> 

<div data-role="popup" id="myPopup1" class="ui-content" style="min-width:250px;"> 

    <form id="localStorageTest" method="post" action=" "> 
    <div class="ui-field-contain"> 
    <label for="fullname">Full name:</label> 
    <input type="text" name="fullname" id="fullname" class = "stored">  

    <label for="email">E-mail:</label> 
    <input type="email" name="email" id="email" placeholder="Your email.." class = "stored"> 
    </div> 
    <input id= "submitcheck" type="submit" data-inline="true" value="Submit"> 
</form> 
</div> 
    </div> 

</body> 
</html> 

的jQuery:

$(document).ready(function() { 

    if (localStorage["name"]&&localStorage["email"]) { 
     window.location.href = "calendar.html";} 
    else {$("<div>Incorrect Entry</div>").dialog();} 



$('#localStorageTest').submitcheck(function() { 
$('.stored').keyup(function() { 
localStorage[$(this).attr('name')] = $(this).val();} 
}); }); 
</script> 
+0

*「按鈕越來越糊塗」 *是不是一個合適的技術問題陳述,它告訴我們什麼值錢的東西。也不知道'submitcheck()'是什麼,因爲它不是一個jQuery核心方法 – charlietfl

回答

0

據我所知,看着你的代碼(我在這裏做了一個小提琴,與您的代碼https://jsfiddle.net/webbm/edfwoxxh/),你想做一些形式的輸入檢查編號localStorageTest

如果你改變你的代碼來使用它,它會打到正確的功能,當你只提交註冊時:

$('#localStorageTest').submit(function() { 
    /* Your code here */ 
}); 

你需要做的不是在那裏$('.stored').keyup其他東西,因爲這並沒有真正意義。如果你要檢查輸入的值,你可以做這樣的事情:

$('#localStorageTest').submit(function() { 
    var fullname = $('#fullname').val(); 
    var email = $('#email').val(); 
    if(fullname) { 
    //fullname has a value 
    } 
});