動態搜索選項2個表

Question

這裏是我的問題，我有2個表這裏涉及到：TINVOICES和TJOBS

TINVOICES - Job_no 
TINVOICES - Year 
TJOBS - Staff 
TINVOICES - Month 
TJOBS - Country 
TINVOICES - Paid 
TJOBS - Client_no 
TINVOICES - 30 Days 

我想要的搜索選項是動態的，像它應該接受搜索工作，今年，獨自一人。或者僅支付或僅僅一個月...等等。我有兩張桌子。 你能幫我解決一下我的方法嗎？

查看我的代碼如下。

太謝謝你了！

這裏是我的搜索選項：

---

if (isset($_POST['job_no'])) { 
     $job_no = $_POST['job_no']; 
     if ($_POST['job_no'] != "") { $job_no = " job_no=".$job_no." AND"; $search += 1;} 
    } 
    ..other ifs 

if ($search != 0) { 
    if (isset($_POST['country'])) { 
     if ($_POST['country'] == "") { 
      $query = "WHERE $job_no$month$id$year$staff_no$paid"; 
     } 
     else { 
      $query = "AND $job_no$month$id$year$staff_no$paid"; 
     } 
    } 
    else{ 
     $query = "WHERE $job_no$month$id$year$staff_no$paid"; 
    } 
}          

//Remove string AND on the end of a query if found 
if (substr($query, -3) == "AND") { $query = substr($query, 0, -3); } 

if (isset($_POST['country']) && $_POST['country'] != "") {  
    $country = $_POST['country']; 
    if ($country == "All") { 
     $sql = "SELECT p . * FROM tinvoices $query AS p "; 
    } 
    else if ($country == "Middle East") { 
     $sql = " 
     SELECT p . * 
     FROM tinvoices AS p 
     LEFT JOIN tjobs AS j 
     ON p.job_no = j.job_no 
     WHERE j.location = 'Qatar' OR j.location = 'UAE' $query "; 
    } 
    else { 
     $sql = " 
     SELECT p . * 
     FROM tinvoices AS p 
     LEFT JOIN tjobs AS j 
     ON p.job_no = j.job_no 
     WHERE j.location = '$country' $query "; 
    } 
    $result = mysqli_query($con,$sql) or die("MySQL Error: ".mysql_error()); 
} 
elseif (isset($_POST['client_no']) && $_POST['client_no'] != "") {  
    $client_no = $_POST['client_no']; 
    $sql = " 
     SELECT p . * 
     FROM tinvoices AS p 
     LEFT JOIN tjobs AS j 
     ON p.job_no = j.job_no 
     WHERE j.location = '$country' $query "; 
    echo $sql; 
} 
else { 
    $sql = "SELECT p . * FROM tinvoices AS p $query"; 
    //echo $sql; 
    $result = mysqli_query($con,$sql) or die("MySQL Error: ".mysql_error()); 
} 

Answer 1

使搜索動態，首先確保表單元素名稱是完全一樣的數據庫表字段。對於兩個表格，您可以在表格名稱前加上表格元素名稱，然後在字段中加前綴。例如

如果你的數據庫字段名稱是tinvoices表位置，然後你的位置元素的名稱應該是tinvoices_location

所以，當提交表單時可以遍歷這樣 發佈的數據假設你有兩條表Table 1和Table

$sql = "SELECT table1.*, table2.* FROM table1 INNER JOIN table2 ON table2.id = table1.table2_column WHERE "; 

$conditions = array(); 
    foreach($_POST as $key => $value){ 
    $tableFields = explode('_', $key); 
    $conditions[] = $tableFields[0].'.'.$tableFields[1].' = "'.$value.'"'; // will produce table1.location = "Qatar" 
    } 
$sql .= implode(' AND ', $conditions); // will produce condtion1 AND condition2 and so on 

$sql .= ' ORDER BY table1.column'; 

在循環中，您還可以使用針對specifi元素

if(preg_match('/table1_/', $key)){ 
//populate conditions array 
} 

接下來，您可以根據需要修改它。