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我有一個很長的道理,我正在使用python的base64.b64decode()
方法進行解碼。爲什麼Python的base64.b64decode()在字符串結尾忽略亂碼?
它的工作原理。但是,如下所示,即使在最後插入亂碼字符,它也會返回相同的結果。爲什麼?這兩個字符串不應該產生兩個不同的解碼結果嗎?
>>> import base64
>>> token = "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"
>>> base64.b64decode("%sXXXXXXBlahBlahBlah" % (token)) == base64.b64decode(token)
True
如果我把亂碼字符開頭,它失敗:
>>> base64.b64decode("%sXXXXXXBlahBlahBlah" % (token)) == base64.b64decode(token)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/usr/local/Cellar/python/2.7.8_2/Frameworks/Python.framework/Versions/2.7/lib/python2.7/base64.py", line 76, in b64decode
raise TypeError(msg)
TypeError: Incorrect padding
@DisplayName:這會是' 「%sXXXXXXBlahBlahBlah」 %(令牌)'。 – user2357112
糟糕。抱歉是。編輯。 –