控制檯窗口不會留在屏幕上，儘管「cin.get（）;」或系統（「暫停」）

Question

我想，只要你運行一個C++程序留在彈出的控制檯窗口......但在我這裏的代碼沒有發生。它很快就消失了。怎麼了？注意：我是C++新手。

由於某些原因，當我僅使用main()函數來保存所有內容而沒有第二個函數時，它正常工作，但爲了我的任務，我無法將所有內容填充到main()。

#include <iostream> 
#include <fstream> 
#include <string> 
#include <vector> 
#include <sstream> 
#include <cstdio> 
using namespace std; 

ifstream file("maze.txt"); 
vector<char> vec(istreambuf_iterator<char>(file), (istreambuf_iterator<char>())); // Imports characters from file 
vector<char> path;      // Declares path as the vector storing the characters from the file 
int x = 18;        // Declaring x as 18 so I can use it with recursion below 
char entrance = vec.at(16);    // 'S', the entrance to the maze 
char firstsquare = vec.at(17);   // For the first walkable square next to the entrance 
vector<char> visited;     // Squares that we've walked over already 

int main() 
{ 
    if (file) { 
     path.push_back(entrance);    // Store 'S', the entrance character, into vector 'path' 
     path.push_back(firstsquare);   // Store the character of the square to the right of the entrance 
               // into vector 'path'. 
     while (isalpha(vec.at(x))) 
     { 
      path.push_back(vec.at(x)); 
      x++; 
     } 
    } 
} 

int printtoscreen() 
{ 
    cout << "Path is: ";     // Printing to screen the first part of our statement 

     // This loop to print to the screen all the contents of the vector 'path'. 
     for(vector<char>::const_iterator i = path.begin(); i != path.end(); ++i) // 
     { 
     std::cout << *i << ' '; 
     } 

     cout << endl; 
     cin.get();       // Keeps the black box that pops up, open, so we can see results. 
     return 0; 
} 

Answer 1

你是不是叫你printoscreen功能。嘗試在main()函數結束之前添加printtoscreen();。

編輯：

而且考慮改變int printoscreen(){到void printoscreen(){和correspondigly return 0;只是return;在此功能，不必返回任何有意義的東西，並ignorig在主要結果值。因此，編碼將是：

#include <iostream> 
#include <fstream> 
#include <string> 
#include <vector> 
#include <sstream> 
#include <cstdio> 
using namespace std; 

ifstream file("maze.txt"); 
vector<char> vec(istreambuf_iterator<char>(file), (istreambuf_iterator<char>())); // Imports characters from file 
vector<char> path;      // Declares path as the vector storing the characters from the file 
int x = 18;        // Declaring x as 18 so I can use it with recursion below 
char entrance = vec.at(16);    // 'S', the entrance to the maze 
char firstsquare = vec.at(17);   // For the first walkable square next to the entrance 
vector<char> visited;     // Squares that we've walked over already 

void printtoscreen(); 

int main() 
{ 
    if (file) { 
     path.push_back(entrance);    // Store 'S', the entrance character, into vector 'path' 
     path.push_back(firstsquare);   // Store the character of the square to the right of the entrance 
               // into vector 'path'. 
     while (isalpha(vec.at(x))) 
     { 
      path.push_back(vec.at(x)); 
      x++; 
     } 
    } 
    printtoscreen(); 
} 

void printtoscreen() 
{ 
    cout << "Path is: ";     // Printing to screen the first part of our statement 

     // This loop to print to the screen all the contents of the vector 'path'. 
     for(vector<char>::const_iterator i = path.begin(); i != path.end(); ++i) // 
     { 
     std::cout << *i << ' '; 
     } 

     cout << endl; 
     cin.get();       // Keeps the black box that pops up, open, so we can see results. 
     return; 
} 

Answer 2

也許，如果你真的稱爲printtoscreen，你可能會發現，它會執行暫停代碼。

但是，實際上，無論如何，我都會在main的末尾放置cin.get()位，只是因爲它只有在IDE中運行時纔有。你可能不想在最終的可執行文件中使用它，因爲它可能會惹惱任何試圖運行它的人。

換句話說，從printtoscreen末尾移除cin.get();，並把這樣的事情在main末：

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而且請記住，您可能需要main之前，無論是移動printtoscreen，或者在main之前提供原型（以便main知道它）。