基於其他變量格式化字符串

Question

處理要求我們輸入的類的賦值，以便基於來自輸入的數字創建「畜欄」。基於另一個變量，我正在努力嘗試獲得正確的間距。畜欄應該是這個樣子：

|==|==|==| 
:  : 
-  - 
:  : 
|==|==|==| 

我的問題是在中心（這應該基於頂部/底部的長度）的空白。 Setw（）在某種程度上起作用，但是再一次，只是一個令人憤怒的時刻。以下是我到目前爲止的其餘內容：'

#include <iostream> 
#include <iomanip> 
using namespace std; 

main() { 

    int theloop,nsfp,ewfp,count,nsfp2,ewfp2,nsfpw,count2; 
    char choice; 
    theloop = 0; 

    while (theloop < 1) { 

     do { 
      cout << "How many North/South Fence posts? "; 
      cin >> nsfp; 
      if (nsfp < 2) 
      cout << "Value must be at least 2, please try again\n"; 
      else if (nsfp > 10) 
       nsfp = 10; 
     } while (nsfp < 2); 

     do { 
      cout << "How many East/West Fence posts? "; 
      cin >> ewfp; 
      if (ewfp < 2) 
       cout << "Value must be at least 2, please try again\n"; 
      else if (ewfp > 10) 
       nsfp = 10; 
     } while (ewfp < 2); 

     for (count = 1; count <= nsfp; count++) { 
      cout << "|"; 
      nsfp2 = nsfp - 1; 
      for (count = 1; count <= nsfp2; count++) { 
       cout << "==|"; 
       nsfpw = count; 
      } 
     } 

     for (count = 1; count < ewfp; count++) { 
      cout << "\n:" << " " << ":" << endl; 
      ewfp2 = ewfp; 
      for (count = 1; count < ewfp2; count++){ 
       cout << "-" << setw(nsfpw) << "-" << "\n:" << ":" << endl; 
      } 
     } 

     cout << "\n" << nsfp << endl; 
     cout << ewfp; 
     theloop = 1; 
    } 
} 

Answer 1

也許你要找的是這個。空格的數量是

3 * nsfp - 4;

#include <iostream> 
#include <iomanip> 
using namespace std; 

main() { 

    int theloop,nsfp,ewfp,count,nsfp2,ewfp2,nsfpw,count2; 
    char choice; 
    theloop = 0; 

    while (theloop < 1) { 

    do { 
    cout << "How many North/South Fence posts? "; 
    cin >> nsfp; 
    if (nsfp < 2) 
     cout << "Value must be at least 2, please try again\n"; 
    else if (nsfp > 10) 
     nsfp = 10; 
    } while (nsfp < 2); 

    do { 
    cout << "How many East/West Fence posts? "; 
    cin >> ewfp; 
    if (ewfp < 2) 
     cout << "Value must be at least 2, please try again\n"; 
    else if (ewfp > 10) 
     nsfp = 10; 
    } while (ewfp < 2); 

    for (count = 1; count <= nsfp; count++) { 
     cout << "|"; 
     nsfp2 = nsfp - 1; 
     for (count = 1; count <= nsfp2; count++) { 
      cout << "==|"; 
      nsfpw = count; 
     } 
    } 
    cout << "\n"; 
    int spaces = 3 * nsfp - 4; 
    for (count = 1; count < ewfp; count++) { 
     cout << ":"; 
     for (int i = 0; i < spaces; i++) { 
      cout << " "; 
     } 
     cout << ":\n-"; 
     ewfp2 = ewfp; 
     for (int i = 0; i < spaces; i++){ 
      cout << " "; 
     } 
     cout << "-\n"; 
    } 
    for (count = 1; count <= nsfp; count++) { 
     cout << "|"; 
     nsfp2 = nsfp - 1; 
     for (count = 1; count <= nsfp2; count++) { 
      cout << "==|"; 
      nsfpw = count; 
     } 
    } 

    cout << "\n" << nsfp << endl; 
    cout << ewfp; 
    theloop = 1; 
    } 
} 

一個更清潔的方式來做到這一點：

#include <iostream> 
#include <iomanip> 
#include <string> 
using namespace std; 

main() { 

    int theloop,nsfp,ewfp,count,nsfp2,ewfp2,nsfpw,count2; 
    char choice; 
    theloop = 0; 

    while (theloop < 1) { 

    do { 
    cout << "How many North/South Fence posts? "; 
    cin >> nsfp; 
    if (nsfp < 2) 
     cout << "Value must be at least 2, please try again\n"; 
    else if (nsfp > 10) 
     nsfp = 10; 
    } while (nsfp < 2); 

    do { 
    cout << "How many East/West Fence posts? "; 
    cin >> ewfp; 
    if (ewfp < 2) 
     cout << "Value must be at least 2, please try again\n"; 
    else if (ewfp > 10) 
     nsfp = 10; 
    } while (ewfp < 2); 

    for (count = 1; count <= nsfp; count++) { 
     cout << "|"; 
     nsfp2 = nsfp - 1; 
     for (count = 1; count <= nsfp2; count++) { 
      cout << "==|"; 
      nsfpw = count; 
     } 
    } 
    cout << "\n"; 
    string spaces(3 * nsfp - 4, ' '); 
    for (count = 1; count < ewfp; count++) { 
     cout << ":" << spaces << ":\n"; 
     cout << "-" << spaces << "-\n"; 
    } 
    for (count = 1; count <= nsfp; count++) { 
     cout << "|"; 
     nsfp2 = nsfp - 1; 
     for (count = 1; count <= nsfp2; count++) { 
      cout << "==|"; 
      nsfpw = count; 
     } 
    } 

    cout << "\n" << nsfp << endl; 
    cout << ewfp; 
    theloop = 1; 
    } 
}