2015-05-22 45 views
0

如何檢查$ enjaz_youm在索引頁每一秒我的系統自動檢查是否聲明PHP

<? 
if($enjaz_youm == 80) { 
    echo "<script>"; 
    echo "alert('This is an alert from JavaScript!');"; 
    echo "</script>"; 
} 
?> 

感謝

+2

我相信你需要AJAX! – someOne

+0

好吧我怎麼能這樣做,我是一個初學者 –

+0

請詳細解釋背景請 – xNeyte

回答

2

你可以試試這個。

<?php 
if ($_POST['action']=='enjaz_youm') { 
    //do your checks here 
    if ($enjaz_youm==80) echo '1'; 
die(); 
} 
?> 
<!DOCTYPE html> 
<html> 
<head> 
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.2/jquery.min.js"></script> 
<script> 
$(document).ready(function() 
{ 
    var refreshId = setInterval(function() 
    { 

     var request = $.ajax({ 
       url: "<?=$_SERVER['PHP_SELF']?>", 
       type: "POST", 
       data: {action : 'enjaz_youm'}, 
       dataType: "html" 
      }); 
      request.done(function(msg) { 
       if (msg=='1') { 
        alert("This is an alert from JavaScript!"); 
       } 
      }); 

    }, 1000); 
}); 
</script> 
</head> 
<body> 
</body> 
</html>