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如何檢查$ enjaz_youm在索引頁每一秒我的系統自動檢查是否聲明PHP
<?
if($enjaz_youm == 80) {
echo "<script>";
echo "alert('This is an alert from JavaScript!');";
echo "</script>";
}
?>
感謝
如何檢查$ enjaz_youm在索引頁每一秒我的系統自動檢查是否聲明PHP
<?
if($enjaz_youm == 80) {
echo "<script>";
echo "alert('This is an alert from JavaScript!');";
echo "</script>";
}
?>
感謝
你可以試試這個。
<?php
if ($_POST['action']=='enjaz_youm') {
//do your checks here
if ($enjaz_youm==80) echo '1';
die();
}
?>
<!DOCTYPE html>
<html>
<head>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.2/jquery.min.js"></script>
<script>
$(document).ready(function()
{
var refreshId = setInterval(function()
{
var request = $.ajax({
url: "<?=$_SERVER['PHP_SELF']?>",
type: "POST",
data: {action : 'enjaz_youm'},
dataType: "html"
});
request.done(function(msg) {
if (msg=='1') {
alert("This is an alert from JavaScript!");
}
});
}, 1000);
});
</script>
</head>
<body>
</body>
</html>
我相信你需要AJAX! – someOne
好吧我怎麼能這樣做,我是一個初學者 –
請詳細解釋背景請 – xNeyte