如何解決在PHP中的以下錯誤？

我有兩個地區和類別的代碼。他們完全一樣。對分類代碼工作，但「區域」返回以下錯誤：如何解決在PHP中的以下錯誤？

Fatal error: Call to a member function getRegion() on null in C:\wamp64\www\site\catalog\controller\module\latest.php on line 81

//地區

$product_region = array(); 
$regions = $this->model_profile_profile->getProductRegions($result['product_id']); 
foreach ($regions as $region_id) { 

print_r($region_id); // !!! ($region_id = 2) !!! $region_id is not empty !!! 
    $region_info = $this->model_account_region->getRegion($region_id); // LINE 81 

    if ($region_info) { 
     $product_region[] = array(
      'name' => ($region_info['path']) ? $region_info['path'] . ' &gt; ' . $region_info['name'] : $category_info['name'], 
      'href' => $this->url->link('account/profile', '&path=' . $region_info['region_id']) 
     ); 
    } 
}

這裏是這可能會導致錯誤的代碼：

public function getRegion($region_id) { 
    $query = $this->db->query("SELECT DISTINCT *, (SELECT GROUP_CONCAT(cd1.name ORDER BY level SEPARATOR '&nbsp;&nbsp;&gt;&nbsp;&nbsp;') FROM " . DB_PREFIX . "region_path cp LEFT JOIN " . DB_PREFIX . "region_description cd1 ON (cp.path_id = cd1.region_id AND cp.region_id != cp.path_id) WHERE cp.region_id = c.region_id AND cd1.language_id = '" . (int)$this->config->get('config_language_id') . "' GROUP BY cp.region_id) AS path, (SELECT DISTINCT keyword FROM " . DB_PREFIX . "url_alias WHERE query = 'region_id=" . (int)$region_id . "') AS keyword FROM " . DB_PREFIX . "region c LEFT JOIN " . DB_PREFIX . "region_description cd2 ON (c.region_id = cd2.region_id) WHERE c.region_id = '" . (int)$region_id . "' AND cd2.language_id = '" . (int)$this->config->get('config_language_id') . "'"); 

    return $query->row; 
}

如果您通過提供一段代碼來幫助我，我會很感激，因爲我在PHP中是虛擬的。

來源

2016-05-29 Kardo

建議。不要硬編碼。嘗試使用CI db類... – Fil

@Fil，那是什麼或如何使用？ – Kardo

這不是解決方案，但我認爲這可以幫助https://codeigniter.com/user_guide/database/index.html – Fil

$this->model_account_region //This property is null

檢查

echo 'FILE : '.__FILE__ .'<br/>'; 
echo 'LINE : '.__LINE__ .'<br/>'; 
echo '<pre>'; 
var_dump(empty($this->model_account_region)); 
echo '</pre>'; 
exit;

來源

2016-05-29 11:11:41

model_account_region模型類搞砸。由於您的時間不夠用了。我建議你複製功能

public function getRegion($region_id) { 
     $query = $this->db->query("SELECT DISTINCT *, (SELECT GROUP_CONCAT(cd1.name ORDER BY level SEPARATOR '&nbsp;&nbsp;&gt;&nbsp;&nbsp;') FROM " . DB_PREFIX . "region_path cp LEFT JOIN " . DB_PREFIX . "region_description cd1 ON (cp.path_id = cd1.region_id AND cp.region_id != cp.path_id) WHERE cp.region_id = c.region_id AND cd1.language_id = '" . (int)$this->config->get('config_language_id') . "' GROUP BY cp.region_id) AS path, (SELECT DISTINCT keyword FROM " . DB_PREFIX . "url_alias WHERE query = 'region_id=" . (int)$region_id . "') AS keyword FROM " . DB_PREFIX . "region c LEFT JOIN " . DB_PREFIX . "region_description cd2 ON (c.region_id = cd2.region_id) WHERE c.region_id = '" . (int)$region_id . "' AND cd2.language_id = '" . (int)$this->config->get('config_language_id') . "'"); 

    return $query->row; 
    }

到model_profile_profile然後調用它從那裏即

$region_info = $this->model_profile_profile->getRegion($region_id); // LINE 81

如果失敗了DB類失敗，所以你打電話就行你的函數之前添加該行正常加載81

$this->load->database();

讓我知道你是否面臨更多挑戰。我對這裏有點無聊。

來源

2016-05-29 11:20:19

如何解決在PHP中的以下錯誤？

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