For循環與如果不按預期方式工作

Question

我有我正在使用的這段代碼。我是一個新手，所以請原諒我的無知。

預期的邏輯是：

在列表Y A值，發現在表S任何匹配並打印出表S（未列出y）處的值。 我目前的代碼打印列表y，但我實際上想要列表s。

這裏是我當前的代碼：

y = ['a','m','j'] 
s = ['lumberjack', 'banana split'] 

for x in s: 
    if any(x in alpha for alpha in y): 
      print x 

我打算打印「樵夫」和「香蕉船」，但該代碼是打印「A」 請幫助:)

謝謝

Answer 1

打印「一」是正確的，如果你想打印「樵夫」，附加到字母列表中的那些字符（即變量y）

y = 'albumjcker' # all characters inside "lumberjack" 
s = 'lumberjack' 

for x in s: 
    if any(x in alpha for alpha in y): 
      print x 

應該做的伎倆

---

嘗試：

y = ["a", "b", "c", "l"] 
s = ["banana split", "lumberjack"] 
for words in s: 
    for char in y: 
     if char in words: 
      print (words) 
      break 

---

y = ["animal","zoo","potato"] 
s = ["The animal farm on the left","I had potatoes for lunch"] 
for words in s: 
    for char in y: 
     if char in words: 
      print (words) 
      break 

The animal farm on the left 
I had potatoes for lunch 

---

編輯

y = ["animal","zoo","potato"] 
s = ["The animal farm on the left","I had potatoes for lunch"] 
s = list(set(s)) # But NOTE THAT this might change the order of your original list 
for words in s: 
    for char in y: 
     if char in words: 
      print (words) 
      break 

如果順序很重要，那麼我想你只能做

y = ["animal","zoo","potato"] 
s = ["The animal farm on the left","I had potatoes for lunch"] 

new = [] 
for x in s: 
    if x not in new: 
     new.append(x) 
s = new 

for words in s: 
    for char in y: 
     if char in words: 
      print (words) 
      break 

Answer 2

在您的for循環中，您只是打印當時正在迭代的字符，而不是完整的字符串。

y = 'a' 
s = 'lumberjack' 

for x in s: 
    if any(x in alpha for alpha in y): 
     print s # Return 'lumberjack' 

編輯如果你有一組字符（如您的意見建議），則：

y = ['a', 'z', 'b'] 
s = 'lumberjack' 

def check_chars(s, chars): 
    for char in y: 
     if char in s: 
      print s 
      break 

for s in ['lumberjack','banana split']: 
    check_chars(s,y) 

此檢查y中的字符串（ 'A'）是否是s的子串（ '伐木工'），它也打破後，你打印，所以你不可能打印多次。