我有兩個查詢$ q1和$ q2。 從query1我得到多個記錄,每個記錄都有id,我想用這個id作爲第二個查詢條件。傳遞兩個查詢結果以在codeigniter中查看
我在控制器中這樣做。 我試過下面的代碼。 在foreach我試圖存儲id並傳遞給$ q2條件。
//Query 1
$q1 = $this->db->select(array(
'spf.id as id' ,
'spf.name',
'spf.added_on'
))->from('sp_form spf')->where($where)->order_by('spf.id desc')->limit(10, $page * 10)->get();
$data['data'] = $q1->result_array();
foreach($data as $rec)
{
$id = $rec['id']; // here how i catch id for each row
//Query 2
$q2 = $this->db->select("count('id') as count ")->from('sp_topic spft')->where('spft.formid',$id)->get();
$data['count'] = $q1->row_object();
}
// pass combine result to view
$this->load->view('myview', $data,true);
編輯:
This is my view.
I have try Nishant answer and i get resultq1 using foreach but how can i get result of resultq2.
<table width="100%">
<tr>
<td class="th"> Details</td>
<td width="5%" class="th"> Answer</td>
<td width="15%" class="th">Started by</td>
<td width="15%" class="th">Created on</td>
</tr>
<?php foreach($resultq1 as $row):?>
<tr>
<td><?php echo $row['name'] ;?></td>
<td >---- </td> // here i want to use resultq2
<td><?php echo $row['added_by'] ;?></td>
<td ><?php echo $row['added_on'];?></td>
</tr>
<?php endforeach;?>
</table>
:我怎樣才能在view.for resultq1 $ resultq2我使用的foreach(),但resultq2只有一個結果。 – Kango 2013-02-28 11:58:28