1
考慮以下幾點:如何在類模板之外定義類模板的構造函數模板?
template<typename R>
struct call {
template<typename F, typename... Args>
explicit call(F&& f, Args&&... args);
R result;
};
template<typename R, typename F, typename... Args>
call<R>::call(F&& f, Args&&... args)
: result(std::forward<F>(f)(std::forward<Args>(args)...)) { }
鐺罵我:
utility.tpp:40:1: error: too many template parameters in template redeclaration template<typename R, typename F, typename... Args> ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ utility.hpp:36:5: note: previous template declaration is here template<typename R> ^~~~~~~~~~~~~~~~~~~~
我完全摸不着頭腦。它有可能嗎?