INNER JOIN：where子句太模糊

Question

我得到錯誤"Integrity constraint violation: 1052 Column 'restaurant_id' in where clause is ambiguous' in"。

a）如何在JOIN上使用bindparam？那甚至是導致這個錯誤的問題？

function restaurant(PDO $dbh, $username) { 
    global $dbh; 
    $stmt = $dbh->prepare(" 
     SELECT  * 
     FROM   users u 
     INNER JOIN menues m 
     ON   u.user_id = m.restaurant_id 
     INNER JOIN users_slider s 
     ON   m.restaurant_id = s.restaurant_id 
     WHERE   restaurant_id = :restaurant_id 
    "); 

    $stmt->bindParam(":restaurant_id", $_GET['r']); 
    $stmt->execute(); 
    return $stmt->fetchAll(); 
} 

Answer 1

變化

... 
WHERE  restaurant_id = :restaurant_id 

到

... 
WHERE  m.restaurant_id = :restaurant_id 
      ^^ 

Answer 2

地方根據自己的條件表，將解決您的問題，請使用m.restaurant_id或s.restaurant_id。

Answer 3

放在哪裏等，其中m.restaurant_id =條件：restaurant_id

function restaurant(PDO $dbh, $username) { 
    global $dbh; 
    $stmt = $dbh->prepare(" 
     SELECT  * 
     FROM  users u 
     INNER JOIN menues m 
     ON   u.user_id = m.restaurant_id 
     INNER JOIN users_slider s 
     ON   m.restaurant_id = s.restaurant_id 
     WHERE  m.restaurant_id = :restaurant_id 
    "); 

    $stmt->bindParam(":restaurant_id", $_GET['r']); 
    $stmt->execute(); 
    return $stmt->fetchAll(); 
} 

Answer 4

始終使用別名，以避免衝突的連接查詢。這裏restaurant_id應該是m.restaurant_id。

嘗試此查詢： -

SELECT  * 
     FROM   users u 
     INNER JOIN menues m 
     ON   u.user_id = m.restaurant_id 
     INNER JOIN users_slider s 
     ON   m.restaurant_id = s.restaurant_id 
     WHERE   m.restaurant_id =:restaurant_id