C++將數組從char轉換爲unsigned int是否正確又安全？

Question

目標：正確快速地將數組從char轉換爲unsigned int。

檢查我的工作 - 請：

... 
// NOTE: 
// m_chFileBuffer is a member/variable from a class. 
// m_nFileSize is also a member/variable from a class. 
// iFile is declared locally as std::ifstream 

// Calculate the size of iFile and copy the calculated 
// value to this->m_nFileSize 
iFile.seekg(0, std::ios::end); 
this->m_nFileSize = iFile.tellg(); 
iFile.seekg(0, std::ios::beg); 

// Declare this->m_chFileBuffer as a new char array 
this->m_chFileBuffer = new char[ this->m_nFileSize ]; 

// Read iFile into this->m_chFileBuffer 
iFile.read(this->m_chFileBuffer, this->m_nFileSize); 

// Declare a new local variable 
::UINT *nFileBuffer = new ::UINT[ this->m_nFileSize ]; 

// Convert this->m_chFileBuffer from char to unsigned int (::UINT) 
// I might be doing this horribly wrong, but at least I tried and 
// will end up learning from my mistakes! 
for(::UINT nIndex = 0; nIndex != this->m_nFileSize; nIndex ++) 
{ 
    nFileBuffer[ nIndex ] = static_cast<::UINT>(this->m_chFileBuffer[ nIndex ]); 

    // If defined DEBUG, print the value located at nIndex within nFileBuffer 
    #ifdef DEBUG 
    std::cout << nFileBuffer[ nIndex ] << ' '; 
    #endif // DEBUG 
} 

// Do whatever with nFileBuffer 
... 

// Clean-up 
delete [ ] nFileBuffer; 

得到的東西？： 如果有更好的方法來完成目標，請後下！

更多： 是否有可能將此概念應用於unsigned int std :: vector？

Answer 1

對於這麼簡單的任務來說代碼太多了，你需要的只是這個。

std::vector <unsigned int> v; 
std::copy (std::istream_iterator <char> (iFile), 
      std::istream_iterator <char>(), 
      std::back_inserter (v)); 

或者更短（感謝@ 111111）：

std::vector <unsigned int> v 
{ 
     std::istream_iterator <char> (iFile), 
     std::istream_iterator <char>() 
}; 

Answer 2

vector<char> buf(file_size); 
/* read file to &buf[0] */ 
vector<unsigned int> uints(buf.size()); 
copy(buf.begin(), buf.end(), uints.begin()); 

你生新/刪除使用率也不例外安全。經驗法則：不要在你的代碼中寫入刪除，只要你不是自己編寫析構函數。此外，「char」可能會被簽名，但不確定你期望在那裏有什麼行爲。